The straight line joining the points A(3,-5) and B(6,k) has a gradient of 4.
Gradient is the slope
So the slope of the line joining the points A(3,-5) and B(6,k) is 4
Slope of line joining two points = 
A(3,-5) and B(6,k) are (x1,y1) and (x2,y2)
slope =
slope = 
We know slope =4
Cross multiply and solve for k
k + 5 = 12
k = 7
The value of k = 7
Answer:
22 is the answer
Step-by-step explanation:
22 is the answer
A. Diagonals bisect each other is always true. Each diagonal<span> cuts the </span>other<span> into two equal parts. It is because of the parallel lines in the parallelogram. </span>
Answer:
Step-by-step explanation:
-3(3/6) + 4(3/5)
-3(1/2) + 4(3/5)
-3/2 + 12/5
-15/10 + 24/10
9/10
1) Change radical forms to fractional exponents using the rule:The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span>
![\sqrt[n]{3} = 3^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7B3%7D%20%3D%20%20%203%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D)
.
The square root of 3 (
) = 3 to the one-half power (
).
The 5th root of 3 (
![\sqrt[5]{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B3%7D%20)
) = 3 to the one-fifth power (
).
2) Now use the product of powers exponent rule to simplify:This rule says
. When two expressions with the same base (a, in this example) are multiplied, you
can add their exponents while keeping the same base.
You now have
. These two expressions have the same base, 3. That means you can add their exponents:
3) You can leave it in the form 
or change it back into a radical ![\sqrt[10]{3^7}](https://tex.z-dn.net/?f=%20%5Csqrt%5B10%5D%7B3%5E7%7D%20)
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Answer:
or
