Answer:
El tiempo que tardarán Lourdes y Rosabel en hacer el trabajo juntas es de 3,6 horas.
Step-by-step explanation:
Los parámetros dados son;
El tiempo que tarda Lourdes en leer las letras = 6 horas
El tiempo que le toma a Rosabel leer las letras = 9 horas
Sea la cantidad total de trabajo de oficina = X
Deje que el tiempo que ambos tienen que trabajar para hacer el trabajo = t
Por lo tanto;
La tasa de trabajo de Lourdes = X / 6
La tasa de trabajo de Rosabel = X / 9
X / 6 × t + X / 9 × t = X
t × (1/6 + 1/9) = 1
t × 5/18 = 1
t = 18/5 = 3,6 horas
Por lo tanto;
El tiempo que les llevará a Lourdes y Rosabel hacer el trabajo juntas = 3.6 horas.
Let S3={I, 1, 2, 3, 4, 5}
Then S3 is an non-Abelian group under composition because ab DNE ba
yet A3 is a normal subgroup of S3 which is commutative and contains permutations of even order
you can also take mappings of this group G
onto G'
may be an isomorphism perhaps
<span>There are 100 * 99 = 9900 different ways to choose two students out of 100 bandmembers. You and our brother are 2 of that ways: you being selected first and you being selected second. Therefore the probability that you two are selected is 2 / 9900 = 0,000202. You can also think as the probability of you being selected among 100 bandmembers, which is 1/100, times the probability of your brother being selected among 99 members, which is 1/99 => (1/100) * (1/99) = 1/ (100*99) = 1 / 9900; plus the same for your brother being selected first and you second => [1/9900] * 2 = 2/9900, which is the same calculated above.</span>
p(x) = 2x3 – x2 + 4x – 7
p(x) = x3 – x2 – x – 3
p(x) = x5 + 4x3 - x2 + 6x