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2 years ago

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1 answer:

larisa [96]2 years ago

5 0

Answer:

wow i have know idea

Explanation:

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A ball is thrown vertically upward with a speed of 19.0 m/s. (a) How high does it rise? m (b) How long does it take to reach its

Arte-miy333 [17]

Answer with Explanation:

We are given that

Initial speed= $u=19 m/s$

a. $g=9.8m/s^2$

Final velocity of ball= $v=0$

$v=u-gt$

g is negative because the ball is going against to gravity.

$0=19-9.8t$

$9.8t=19$

$t=\frac{19}{9.8}=1.94 s$

$s=ut-\frac{1}{2}gt^2$

Using the formula

$s=19(1.94)-\frac{1}{2}(9.8)(1.94)^2$

$s=18.4 m$

a.The ball rise upto height 18.4 m

b.It take 1.94 s to reach its highest point.

c.Initial velocity=0,s=18.4 m

$s=ut+\frac{1}{2}gt^2$

$18.4=0(t)+\frac{1}{2}(9.8)t^2$

$18.4=4.9t^2$

$t^2=\frac{18.4}{4.9}$

$t=\sqrt{\frac{18.4}{4.9}}$

$t=1.94 s$

$v=u+gt$

Using the formula

$v=0+9.8(1.94)=19 m/s$

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Explanation:

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astraxan [27]

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(1) Color

(2) Hardness

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