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3 years ago

What are parts of a pulley

Physics

1 answer:

PtichkaEL [24]3 years ago

3 0

Wheel, axel and rope

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Two very small spherical metal objects, each with 1 coulomb of charge, are brought together in a vacuum so that the separation d

DaniilM [7]

Answer: 9*10^15 N

Force=kqq/r^2

F=[(9*10^9)(1)(1)]/.001^2=9.0*10^15

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3 years ago

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What is a volcanically active area that is not near a tectonic plate boundary?

belka [17]

It a blue tectonic movement

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3 years ago

I need to know the answer to the question

galben [10]

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3 years ago

How much work w is done by the electrostatic force on the moving point charge?

V125BC [204]

As we know that electrostatic force is a conservative force

so we can say by the condition of conservative force

$F_c = -\frac{dU}{dr}$

here we can rearrange the above equation as

$dU = - F_c.dr$

now integrate both sides

$\int dU = - \int F_c . dr$

Now we know by the definition of work done by a force is given by

$W = \int F.dr$

now work done by conservative force is given as

$W_c = \int F_c . dr$

Now from above work done by electric field to move charge from one point to other is given as

$W_{EF} = \int F_{e}.dr = - \int dU$

so here work done is given as

$W_{EF} = U_i - U_f$

so change in potential energy is given by work done

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3 years ago

A car slams on the brakes to stop. The road pushes back up on the car with a normal force of 12,750 N and friction from the brak

ivann1987 [24]

Answer:

$\displaystyle \mu_d=0.75$

Explanation:

Coefficients of Friction

Objects in physical contact produce friction which usually manifests as thermal energy being dissipated in the surface where the objects are interacting. It's usually harder to start to move an object from rest, that keeps moving it at a constant speed on the same surface. That is why there are two different coefficients of friction: the static and the dynamic. As mentioned, the static coefficient $\mu_s$ is greater than the dynamic coefficient $\mu_d$ . The car is already moving and is attempting to stop. The coefficient of friction is defined as

$\displaystyle \mu_d=\frac{F_r}{N}$

Where Fr is the force of friction and N is the normal or the force the road pushes back up on the car. With the given data, we have

$\displaystyle \mu_d=\frac{9,560\ N}{12,750\ N}$

$\displaystyle \boxed{\mu_d=0.75}$

The coefficient of friction is dimensionless (doesn't have any units)

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3 years ago