What are parts of a pulley

In addition to ash, what is produced when wood burns

Genrish500 [490]

I believe the answer is: B (oxygen and carbon dioxide)

I am not for sure, but good luck!

8 0

3 years ago

Can someone please answer this, ill give you brainliest Would be very appreciated.

Whitepunk [10]

Answer:

frost wedging

Explanation:

When glaciers melt and the rock beneath is weathered and broken down, this is called frost wedging.

6 0

2 years ago

Hi!!I need sum help with this bc my teacher told me it had to be more specific!

Elenna [48]

"Frequency" means how often something happens. When you say how many times it happens every SECOND, you can call the number Hertz, or Hz.

In the graph, there are 10 vibrations in 10 seconds, 20 of them in 20 seconds, and 30 in 30 seconds. This should pretty much shout at you "THERE'S ONE VIBRATION EVERY SECOND !". When you realize that, you can say the frequency of the vibration is 1 Hz.

The graph tells us nothing about the speed of the waves. I suspect there's another picture to the question that you didn't include. If the other part shows the wavelength, then we could figure out the speed. But with just what you're showing us, we can't.

7 0

3 years ago

A golf club exerts an average horizontal force of 1000 n on a 0.045 -kg golf ball that is initially at rest on the tee. the club

OlgaM077 [116]

The impulse (the variation of momentum of the ball) is related to the force applied by
$\Delta p = F \Delta t$
where $\Delta p$ is the variation of momentum, F is the intensity of the force and $\Delta t$ is the time of application of the force.
Using F=1000 N and $\Delta t = 1.8 ms=1.8 \cdot 10^{-3}s$ , we can find the variation of momentum:
$\Delta p = (1000 N)(1.8 \cdot 10^{-3} s)=1.8 kg m/s$

This $\Delta p$ can be rewritten as
$\Delta p = p_f - p_i = mv_f - mv_i$
where $p_f$ and $p_i$ are the final and initial momentum. But the ball is initially at rest, so the initial momentum is zero, and
$\Delta p = mv_f$
from which we find the final velocity of the ball:
$v_f = \frac{\Delta p }{m}= \frac{1.8 kg m/s}{0.045 kg}= 40 m/s$

8 0

3 years ago

SHOW ADEQUATE WORKINGS IN THIS SECTION

cluponka [151]

Answer:

12 i. The work done by Wale = 107.910 kJ

The work done by Lekan = 117.720 kJ

Total work done = 225.36 kJ

ii. Wale's power = 4.3164 kW

Lekan's power = 3.924 kW

Wale has more power and is more powerful than Lekan

13. 313.92 N

Explanation:

i. The work done, W = Force, F × Distance moved by the force, D

The given parameters are

The mass of Wale = 55 kg

The mass of Lekan = 60 kg

The acceleration due to gravity, g =9.81 m/s²

The motion force of Wale and Lekan are;

Motion force of Wale = 9.81 × 55 = 539.55 N

Motion force of Lekan = 9.81 × 60 = 588.6 N

The work done by Wale = 539.55 × 200 = 107910 J = 107.910 kJ

The work done by Lekan= 588.6 × 200 = 117720 J = 117.720 kJ

107910 + 117720 =225630 J = 225.36 kJ

ii. Power = Work done/time

Wale finished the race in 25 s, therefore, his power = 107910/25 = 4316.4 W

Lekan finished the race in 30 s, therefore, his power = 117720/30 = 3924 W

Wale has more power and is more powerful than Lekan

13. The velocity ratio = 5

V. R. = Distance moved by effort/(Distance moved by load)

Efficiency = 80%

Work done by effort = x

Work done by machine = Efficiency × Work done by effort = 0.8 × x

Distance moved by effort, E = V. R. × Distance moved by load, D = 5 × D

Work done by effort = Force × Distance moved = 200×9.81× E

Work done by effort = 1962×E = 1962×E = 1962×5×D

Work done by machine = 1962 × D, when D = 1, we have;

0.8 × 1962×1 = 1569.6 J

Work done by effort = Force × Distance moved

Work done by effort = Force × 5×D = Force × 5 (D = 1)

From the principle of conservation of energy, we have;

Energy is neither created nor destroyed

Therefore

Work done by effort = Force × 5 = 1569.6 J

Force = 1569.6 /5 = 313.92 N.

3 0

3 years ago