Well 85% of 25 is 21.25. So the closest ones would be 20 or 22. Well let's check out the difference's. 21.25-20= 1.25.....22-21.25=.75. well clearly .75 is smaller than 1.25 so your answer would be 22. 85% of 25 is closest to 22.
Alright, so 3f-g=4 and f+2g=5.
3f-g=4
f+2g=5
Multiplying the first equation by 2 and adding it to the second, we get 7f=13 and by dividing both sides by 7 we get f=13/7. Since f+2g=5, then we can plug 13/7 in for f to get 13/7+2g=5. Next, we subtract 13/7 from both sides to get 2g=3+1/7=22/7 (since 3*7=21 and 21+1=22). DIviding both sides by 2, we get 22/14=g. Plugging that into f/39g, we get (13/7)/(22*39/14)
= (13/7)/(858/14)
= (13/7)*(14/858)
=182/6006
= 91/3003 (by dividing both numbers by 2)
= 13/429 (by dividing both numbers by 7)
= 1/33 (by dividing both numbers by 13)
Answer:
Yes, an arrow can be drawn from 10.3 so the relation is a function.
Step-by-step explanation:
Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.
The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.
In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.
However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.
Answer: 2916
Step-by-step explanation: hope it helps
Answer:
Step-by-step explanation:
Find the equation of the segment going from (0,-5) to (3,7)
y intercept = -5
Slope = (-5 - 7) / (0 - 3) = -12/-3 = 4
equation: y = 4x - 5
g(x) = x^2 / f(x)
f(x)= (4x - 5)
g(x) = x^2 / (4x - 5)
g'(x) = x^2 * (4x - 5)^-1
g'(x) = 2x*(4x - 5)^-1 + (-1) *4* x^2 (4x - 5)^-2
I will leave that monster the way it is and just find g'(1)
g'(1) = 2(1) * (4(1) - 5)^-1 + (-1) (1)^2 *4* (4(1) - 5)^-2
g'(1) = 2(1) * (-1)^-1 + (-1) (1)^2 *4 * (-1)^2
g'(1) = -2 + (-1) (1)^2 (4)
g'(1) = - 2 + (-1) (1)^2 (4)
g'(1) = - 2 - 4
g'(1) = - 6
