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artcher [175]
3 years ago
15

Same diagram... Which location shows SUMMER in the SOUTHERN hemisphere? *

Physics
2 answers:
Maksim231197 [3]3 years ago
8 0
Location one is the answer
LiRa [457]3 years ago
7 0
Location 1 is correct
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How much heat is needed to change the temperature of 3 grams of gold (c = 0.129 ) from 21°C to 363°C? The answer is expressed to
Temka [501]

Q= mcΔT

Where Q is heat or energy

M is mass, c is heat capacitance and t is temperature

You have to convert Celsius into kelvin in order to use this formula I believe

Celsius + 273 = Kelvin

21 + 273 = 294K

363 + 273 = 636K

Now...

Q= (0.003)(0.129)(636-294)

Q= 0.132 J if you are using kilograms, in terms of grams which seems more appropriate the answer would be 132J of energy.  

3 0
3 years ago
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Kazeer [188]
DO YOU HAVE THE ENGLISH TRANSLATION?
5 0
3 years ago
In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th
Georgia [21]

Explanation:

Given that,

Frequency in the string, f = 110 Hz

Tension, T = 602 N

Tension, T' = 564 N

We know that frequency in a string is given by :

f=\dfrac{1}{2L}\sqrt{\dfrac{T}{m/L}}, T is the tension in the string

i.e.

f\propto\sqrt{T}

\dfrac{f}{f'}=\sqrt{\dfrac{T}{T'}}, f' is the another frequency

{f'}=f\times \sqrt{\dfrac{T'}{T}}

{f'}=110\times \sqrt{\dfrac{564}{602}}

f' =106.47 Hz

We need to find the beat frequency when the hammer strikes the two strings simultaneously. The difference in frequency is called its beat frequency as :

f_b=|f-f'|

f_b=|110-106.47|

f_b=3.53\ beats/s

So, the beat frequency when the hammer strikes the two strings simultaneously is 3.53 beats per second.

8 0
3 years ago
Please Help Me And Also Remember To Number The Answer
Anastasy [175]

The pace at which an object's momentum changes is defined by force. Momentum is the motion of an item. When an item moves with double the velocity, its momentum doubles. As you change the speed of an object, the force causes it to change momentum. So momentum is the product of force and time.

1. Momentum = 100kg.m/s

Momentum is the motion contained in any object/ mass and is simply the product of mass and velocity

So momentum = mass × velocity

Momentum = 25× 4

= 100kg.m/s

2. As, we know momentum = mass × velocity

that is p = mv

we have momentum (p) = 2 kg m/s and velocity (v) = 8 m/s

so substitute values in p=mv

2 kg m/s = m × 8 m / s

m = 2 / 8 kg = 0.25 kg

Therefore, mass of substance is 0.25 kg.

3. Momentum(M) = mass(m) x velocity(v)

Given: mass(m) = 25 kg and momentum(M) = 125 (kgxm)/sec

125 = 25 x v

v = 5 m/sec

The car is going 5 m/s

4. Weight = 1.4 N

we need to calculate mass first,

mass = weight / g

mass = 1.4 / 9.8

= 0.142 kg

momentum = mass × velocity

momentum = 0.142 × 44.7

Momentum = 6.3474 kg m/s

For 1. Momentum = 100kg.m/s, 2. mass of substance is 0.25 kg, 3. The car is going 5 m/s, 4. Momentum = 6.3474 kg m/s

Learn more about momentum here

brainly.com/question/1042017

#SPJ9

8 0
1 year ago
Please help ASAP. A car engine with a mass of 1750 kg can exert 215 000 W. a) How long will it take the car to reach 95.0 km/h i
tensa zangetsu [6.8K]
<h2>Answer:</h2><h3><u>QUESTION①)</u></h3>

<em>✔ First step : calculate the kinetic energy that this car requires to reach 95 km/h</em>

95/ 3,6 ≈ 26,4 m/s  

<em>Ec = ½ m x V²  </em>

With Ec in J; m in kg; and V in m/s  

  • Ec = ½ 1750 x 26,4²  
  • Ec ≈ 610 000 J

<em>✔ Knowing that the car has a p power of 215,000 W, so : </em>

T = E/P  

  • T = 610 000/215 000  
  • T ≈ 2.8 s
<h3>The car takes 2.8 s to reach 95 km/h </h3>

<h3><u>QUESTION②)</u></h3>

N = 2,8/6,5 x 100 = 43.07

<h3>The car efficiency is 43 % </h3>
5 0
3 years ago
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