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Andre45 [30]
3 years ago
13

Ice at -50 oF and 1.00 atmis to be melted in a continuous flow process with saturated steam at 1 bar. Find the minimum quantity

of steam required per pound of ice.The heat capacity of ice is 0.45 Btu/lbmoF.
Physics
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

The minimum quantity of steam required per pound of ice is -22.5 BTU/lbm

Explanation:

Q = mCT

Q/m = CT

Q/m is the quantity of steam required per pound of ice

C is the heat capacity of ice = 0.45 BTU/lbm°F

T is the temperature of ice = -50 °F

Q/m = 0.45 BTU/lbm°F × -50 °F = -22.5 BTU/lbm

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an object is thrown into the air with an initial velocity of 12 meters per seconds from a platform that is raised 4 meters above
butalik [34]

Answer:

1.52 seconds

Explanation:

Step 1: identity the given parameters

Initial velocity (u) = 12m/s

Height above ground (h1) = 4m

Final velocity (V) = 0

Step 2: calculate the height travelled by the object from 4m height (h2).

V^2 = U^2 -2gh

0= 12^2-2(9.8*h)

2(9.8*h) = 12^2

19.6*h = 144

h = 144/19.6

h = 7.347 m

Total height above ground (ht) = 4m +7.347m = 11.347m

Step 3: calculate the time reach ground

T = √(2h/g)

T = √(2*11.347/9.8)

T= √(22.694/9.8)

T= √2.316

T= 1.52 seconds

8 0
3 years ago
Do the rock layers from the various locations that you investigated record evidence of an asteroid impact on Earth? Make a CLAIM
KiRa [710]

Answer:

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8 0
3 years ago
HURRY URGENT ASAP I WILL GIVE BRAINLIEST
Leto [7]

Answer:

A

Explanation:

4 0
3 years ago
A load of 45N attached to a spring that is hanging vertically stretches the spring 0.14m. What is the spring constant?
Vesna [10]
6.3 That Would be the I answer I think but Check on Google For the formula
6 0
3 years ago
Anuja is holding a stuffed dog, with a mass of 0.30 kg, when Derek decides that he wants it and tries to pull it away from Abuja
igor_vitrenko [27]

Answer:

a = 3.33 m/s²

Explanation:

The horizontal acceleration of the dog can be found by using Newton's Second Law of Motion as follows:

F = ma

where,

F = Unbalanced force applied on the dog = 11 N - 10 N = 1 N

m = mass of the dog = 0.3 kg

a = horizontal acceleration of dog = ?

Therefore,

1 N = 0.3 kg(a)

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