Answer:
<h2>Tum karo yaar </h2>
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The mode in this case would be 125 because it occurs the most in the sequence of numbers.
Answer:
Force=7.71KN in the opposite direction
Explanation:
Given the mass of the car(M)=1000Kg
The initial speed of the car(u)=100km/hr
we know that 1km/hr=5/18 m/sec
100km/hr=100*5/18 m/sec=27.77m/sec
the distance travelled before it stops (s)=50m
let the acceleration of the car be a
The final velocity of the car is 0.
we know that
a=7.712m/
We know that F=Ma
F=1000* 7.712=7712N=7.71KN
Answer:
Final velocity will be equal to 14 m/sec
Explanation:
We have given initial velocity u = 5 m/sec
Constant acceleration is given
Time t = 6 sec
We have to find the final velocity
From first equation of motion , here v is final velocity, u is initial velocity , a is acceleration and t is time
So
So equal final velocity will be equal to 14 m/sec
<h2>
Velocity of 0.2 kg ball is 0.17 m/s</h2>
Explanation:
Let the mass of balls be m and M.
Initial velocity ball 1 be u₁, ball 2 be u₂
Final velocity ball 1 be v₁, ball 2 be v₂
Initial momentum = m x u₁ + M x u₂ = 0.2 x 0.3 + 0.1 x 0.1 = 0.07 kgm/s
Final momentum = m x v₁ + M x v₂ = 0.2 x v₁ + 0.1 x 0.36 = 0.2v₁ + 0.036
We have momentum conservation
Initial momentum = Final momentum
0.07 = 0.2v₁ + 0.036
v₁ = 0.17 m/s
Velocity of 0.2 kg ball is 0.17 m/s