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3 years ago

Amount consumed from each food group depends on their age,gender,and physical activity of a person

Physics

2 answers:

Masteriza [31]3 years ago

7 0

Answer:

true

Explanation:

Len [333]3 years ago

5 0

I think you wanted to know whether the statement given is true or false. Based on this assumption, i am trying to answer the question as accurately as possible and hope that it helps. It is a true statement that amount consumed from each food group depends on their age, gender and physical activity of a person. A sportsman will consume a different amount from each food group than a normal person is a simple example.

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How many outer-orbital electrons are found in an atom of:a) Na?b) P?c) Br?d) I?e) Te?f) Sr?

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Answer:

Na=1
P=5
Br=7
I=7
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2 years ago

The magnification of a microscope is increased when_________.

azamat

Answer:

Option B

Explanation:

Magnification of Microscope is

$M = M_o \times M_e$

Mo= Magnification of objective lens and

Me= magnification of the eyepiece.

Both magnifications( of objective and eyepiece) are inversely proportional to the focal length.

Magnification,

$M \propto \dfrac{1}{f}$

when the focal length is less magnification will be high and when the magnification is the low focal length of the microscope will be more.

Thus. Magnification will increase by decreasing the focal length.

The correct answer is Option B

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4 years ago

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3 years ago

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What minerals attracts iron nails?

Helga [31]

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4 years ago

Using energy considerations, calculate the average force (in N) a 67.0 kg sprinter exerts backward on the track to accelerate fr

Illusion [34]

Answer:

$F_{sprinter}=110.4N$

Explanation:

Given data

Mass m=67.0 kg

Final Speed vf=8.00 m/s

Initial Speed vi=2.00 m/s

Distance d=25.0 m

Force F=30.0 N

From work-energy theorem we know that the work done equals the change in kinetic energy

W=ΔK=Kf-Ki=1/2mvf²-1/2mvi²

And

$W=F_{total}.d$

$W=1/2mv_{f}^2-1/2mv_{i}^2\\F_{total}=\frac{1/2mv_{f}^2-1/2mv_{i}^2}{d} \\F_{total}=\frac{1/2(67.0kg)(8.00m/s)^2-1/2(67.0kg)(2.00m/s)^2}{25.0m} \\F_{total}=80.4N$

and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N

$F_{sprinter}=F_{total}+F_{wind}\\F_{sprinter}=80.4N+30N\\F_{sprinter}=110.4N$

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3 years ago

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