Answer:
<h2>10 L</h2>
Explanation:
The new volume can be found by using the formula for Boyle's law which is
![P_1V_1 = P_2V_2](https://tex.z-dn.net/?f=P_1V_1%20%3D%20P_2V_2)
From the question we have
![V_2 = \frac{P_1V_1}{P_2} \\](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7BP_1V_1%7D%7BP_2%7D%20%20%5C%5C)
From the question we have
![V_2 = \frac{40 \times 20}{80} = \frac{800}{80} = 10 \\](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7B40%20%5Ctimes%2020%7D%7B80%7D%20%20%3D%20%20%5Cfrac%7B800%7D%7B80%7D%20%20%3D%2010%20%5C%5C%20)
We have the final answer as
<h3>10 L</h3>
hope this helps you
Answer: The molality of solution is 1.2 mole/kg
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
where,
n = moles of solute
= weight of solvent in kg
Given : 10 g of glycerol is present in 100 g of solution
moles of glycerol = ![\frac{\text {given mass}}{\text {molar mass}}=\frac{10g}{92g/mol}=0.108mol](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bgiven%20mass%7D%7D%7B%5Ctext%20%7Bmolar%20mass%7D%7D%3D%5Cfrac%7B10g%7D%7B92g%2Fmol%7D%3D0.108mol)
mass of water (solvent )= (100-10) = 90 g = 0.09 kg
Now put all the given values in the formula of molality, we get
Therefore, the molality of solution is 1.2 mole/kg
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Answer:
Substances are used up in a reaction.
Explanation:
Answer:
The answer is 375.54 g of AgBr
Explanation:
Mass (g) = Concentration (mol/L) x volume (L) x Molecular Weight of AgBr (g/mol)
Mass = 2M x 1L x 187.77 g/mol
Mass = 375.54g