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Zigmanuir [339]
2 years ago
14

WILLL GIVE BRAINLIEST IF YOU ANSWERRR PLEASEEEE IM LITERALLY BEGGING YOU I PUT THIS QUESTION IN SOO MANY TIMES I HAVEN'T GOTTEN

AN ANSWER PLEASEEE HELPPP

Chemistry
1 answer:
tino4ka555 [31]2 years ago
6 0

Answer:

The answer is 375.54 g of AgBr

Explanation:

Mass (g) = Concentration (mol/L) x volume (L) x Molecular Weight of AgBr (g/mol)

Mass = 2M x 1L x 187.77 g/mol

Mass = 375.54g

You might be interested in
How many atoms are in 0.500mol of calcium?
creativ13 [48]

Answer:

3.01×10²³ atoms of calcium

Explanation:

number of moles = number of atoms/Avogadro's constant

n = N/NA

N = n×NA = 0.500 mol×6.02×10²³ mol^-1

N = 3.01×10²³ atoms of calcium

3 0
3 years ago
How many liters of ammonia (NH3), at 3.2 atm and 23C, must be used to produce of 2.65 grams of calcium hydride (CaH2). 6 Ca(s)
7nadin3 [17]

Answer:

The answer to your question is    V = 0.32 L

Explanation:

Data

Volume of NH₃ = ?

P = 3.2 atm

T = 23°C

mass of CaH₂ = 2.65 g

Balanced chemical reaction

               6Ca  +  2NH₃   ⇒   3CaH₂  +  Ca₃N₂

Process

1.- Convert the mass of CaH₂ to moles

-Calculate the molar mass of CaH₂

 CaH₂ = 40 + 2 = 42 g

                             42 g ------------------ 1 mol

                              2.65 g --------------  x

                              x = (2.65 x 1)/42

                              x = 0.063 moles

2.- Calculate the moles of NH₃

                     2 moles of NH₃ --------------- 3 moles of CaH₂

                      x                        --------------- 0.063 moles

                                x = (0.063 x 2) / 3

                                x = 0.042 moles of NH₃

3.- Convert the °C to °K

Temperature = 23°C + 273

                      = 296°K

4.- Calculate the volume of NH₃

-Use the ideal gas law

              PV = nRT

-Solve for V

                V = nRT / P

-Substitution

                V = (0.042)(0.082)(296) / 3.2

-Simplification

               V = 1.019 / 3.2

-Result

               V = 0.32 L

7 0
3 years ago
when Mn2 ions are separated from the mixture, they go through a series of oxidizing and reducing steps. Write the reaction equat
goldfiish [28.3K]

Answer: hello some part of your question is missing below is the missing part

when H₂O and H₂O₂ is added to Mn(OH)₂(s) and put in water bath to dissolve

answer : attached below

Explanation:

When Mn²⁺ ions are separated from the mixture, attached below are the requires reaction equations that shows the process of separation.

Mn²⁺ ions are separated to the right of the reaction  equations

8 0
3 years ago
What is the purpose of finding oxidation states in the half-reaction method for balancing equations?
vazorg [7]

Answer:

B. To Identify the half reactions for the equation

4 0
3 years ago
A customer experiences worsening side effects in response to a prescription. What do you suggest to them?
o-na [289]

Answer:

Probably stop taking the prescribed durg and contact your pharmacist and your doctor that gave you your prescription asap.

Explanation:

Both of those health professionals will assist the patient in understanding how to go about the next steps for side effect relief.

8 0
2 years ago
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