Question

Please write the equation and help me solve. please no links

Answer 1

Answer: The molality of solution is 1.2 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molality=\frac{n}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in kg

Given : 10 g of glycerol is present in 100 g of solution

moles of glycerol = $\frac{\text {given mass}}{\text {molar mass}}=\frac{10g}{92g/mol}=0.108mol$

mass of water (solvent )= (100-10) = 90 g = 0.09 kg

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.108mol}{0.09kg}=1.2mole/kg$

Therefore, the molality of solution is 1.2 mole/kg