Answer:
c
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
The translation represented by ![\left[\begin{array}{ccc}1\\4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
interprets as a shift of 1 unit to the right ( add 1 to x- coordinate ) and a
shift of 4 units down ( subtract 4 from the y- coordinate ), then
(1, 4 ) → (1 + 1, 4 - 4 ) → (2, 0 )
(4, 4 ) → (4 + 1, 4 - 4 ) → (5, 0 )
(6, 2 ) → (6 + 1, 2 - 4 ) → (7, - 2 )
(1, 2 ) → (1 + 1, 2 - 4 ) → (2, - 2 )
Answer:
B
Step-by-step explanation:
the domain of f(x)= x2 +1 is limited to {0,1,2,3)
the maximum value will be at the maximum value of x which is at x = 3
So, the maximum value of the range will be = 3^2 + 1 = 9 + 1 = 10
Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula

where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,

or, 
or, 
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change = 
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.