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2 years ago

7

454 / 762 = ?

2 answers:

Maslowich2 years ago

6 0

Answer:

huh-

Step-by-step explanation:

Tresset [83]2 years ago

4 0

Ok this is supposed to be about school work stuff not stuff about anime

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Identify the sequence as arithmetic, geometric, or neither. Explain your answer.

mestny [16]

This sequence (1.6, 0.8, 0.4, 0.2,... ) is geometric.
We have formula for any member of geometric sequence: $a_{n} = a_{1}* q^{n-1}$ If a1=1.6 then: $0.8=1.6*q, 0.4=1.6* q^{2}, 0.2=1.6* q^{3}$ The solution for all these equations is: q=0.5. We have: a1=1.6, q=0.5 and this is geometric sequence.

4 0

2 years ago

$650 is invested in an account earning 8.6% interest (APR), compounded monthly. Write a function showing the value of the accoun

IRISSAK [1]

Answer:

The value of the acount after t years is of $A(t) = 650(1.0072)^{12t}$

The annual growth rate is of 0.72%.

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

$A(t) = P(1 + \frac{r}{n})^{nt}$

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

$650 is invested in an account earning 8.6% interest (APR), compounded monthly.

This means that $P = 650, r = 0.086, n = 12$ . So

$A(t) = P(1 + \frac{r}{n})^{nt}$

$A(t) = 650(1 + \frac{0.086}{12})^{12t}$

$A(t) = 650(1.0072)^{12t}$

The value of the acount after t years is of $A(t) = 650(1.0072)^{12t}$

Annual growth rate

1.0072 - 1 = 0.0072 = 0.72%

The annual growth rate is of 0.72%.

5 0

2 years ago

A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

Helen [10]

Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

3 0

3 years ago

What is the awnser to the problem b-9.5<7

OlgaM077 [116]

Answer:

b < 16.5

Step-by-step explanation:

b - 9.5 + 9.5 < 7 + 9.5

b < 16.5

hope this helped :D

5 0

2 years ago

Find the measure of c

guajiro [1.7K]

Answer:

B is the correct answer of this question

3 0

2 years ago