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sattari [20]
4 years ago
6

Determine whether or not baco3 will be more soluble in acidic solution than in pure water.

Chemistry
1 answer:
Volgvan4 years ago
4 0
Barium carbonate (BaCO₃) <span>will be more soluble in acidic solution than in pure water, because Ksp (solubility constant) in water for this salt is very low.
In acid (for example hydrochloric acid) barium carbonate dissolves more because it forms weak electrolyte carbonic acid:
BaCO</span>₃(s) + 2HCl(aq) → BaCl₂(aq) + H₂CO₃(aq).
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The student repeated the experiment using a higher concentration of acid. The same volume of acid and the same mass of magnesium
Elena L [17]

Answer:

53 cm³

Explanation:

When the student used dilute sulfuric acid, the reaction was complete after 60 s, because no more hydrogen was formed in the next 10 s.

The reaction would go faster if the student used a more concentrated acid, but 53 cm³ of hydrogen is the most that would form.

5 0
3 years ago
The heat of combustion (∆H) for an unknown hydrocarbon is -8.21 kJ/mol. If 0.424 mol of the hydrocarbon is burned in a bomb calo
klio [65]

When 0.424 moles of an unknown hydrocarbon (∆Hc = -8.21 kJ/mol) is burned in a bomb calorimeter (C = 1.12 kJ/°C), the change in the temperature is 3.10 °C.

The heat of combustion (∆Hc) for an unknown hydrocarbon is -8.21 kJ/mol. The heat released by the combustion of 0.424 moles of the hydrocarbon is:

Qc = 0.424 mol \times \frac{(-8.21kJ)}{mol} = -3.48 kJ

According to the law of conservation of energy, the sum of the heat released by the combustion (Qc) and the heat absorbed by the bomb calorimeter (Qb) is zero.

Qc + Qb = 0\\\\Qb = -Qc = 3.48 kJ

Given the heat absorbed by the bomb calorimeter (Qb) and the heat capacity of the bomb calorimeter (C), we can calculate the temperature change (ΔT) using the following expression.

Qb = C \times \Delta T\\\\\Delta T = \frac{Qb}{C} = \frac{3.48 kJ}{1.12 kJ/\° C } = 3.10 \° C

When 0.424 moles of an unknown hydrocarbon (∆Hc = -8.21 kJ/mol) is burned in a bomb calorimeter (C = 1.12 kJ/°C), the change in the temperature is 3.10 °C.

Learn more: brainly.com/question/24245395

8 0
3 years ago
Which procedure(s) decrease(s) the random error of a measurement:
PolarNik [594]

Taking the average of more measurements decreases random error of measurement

Taking the average of many measurements is the most effective way to reduce random errors in a measurement. Because the certainty of the results grows as the number of data does, Less risk of random errors means that the value is more certain. Fewer measurements lead to less reliable data collection, which raises the likelihood of random errors.

The complete question is

Which procedure(s) decrease(s) the random error of a measurement: (1) taking the average of more measurements: (2) calibrating the instrument; (3) taking fewer measurements? Explain

To learn more about random errors:

brainly.com/question/14149934

#SPJ4

8 0
2 years ago
If 38 gr of water are produced in reaction, how many mole are CO2 are produced.​
Nataly_w [17]
0.86 moles of CO2 - i’m not sure if this is right but it should be something like that
6 0
3 years ago
Which predator is typically found in Central Africa (but occasionally at geocode 34.043021, -118.2668356) and slays its opponent
noname [10]
I believe it is a black mamba.
6 0
3 years ago
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