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Burka [1]
3 years ago
6

A student lives in a place that receives lots of snow and ice during the winter. The student has observed that the highway depar

tment spreads salt on the road after a snowfall. Which of the following correctly explains why the highway department uses salt on the roads?
Salt lowers the freezing point of water, which makes the melted snow on the road less likely to form ice.

Salt raises the freezing point of water, which makes the melted snow on the road less likely to form ice.

Salt raises the vapor pressure of water, which makes the melted snow more likely to evaporate before it freezes.

Salt lowers the osmotic pressure of water, which makes the melted snow more likely to be absorbed into the ground before it freezes.
Chemistry
2 answers:
trapecia [35]3 years ago
7 0

Answer:

Salt lowers the freezing point of water, which makes the melted snow on the road less likely to form ice.

Annette [7]3 years ago
7 0

Answer:

A

Explanation:

Edge.

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Answer:

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3 years ago
How many moles are contained in 2.0 L of N2 at standard temperature and pressure.
GuDViN [60]

0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.

Explanation:

Data given:

volume of the nitrogen gas = 2 litres

Standard temperature = 273 K

Standard pressure = 1 atm

number of moles =?

R (gas constant) = 0.08201 L atm/mole K

Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law

PV = nRT

rearranging the  equation to calculate number of moles:

PV = nRT

n = \frac{PV}{RT}

putting the values in the equation:

n = \frac{1X2}{0.08201 X 273}

n = 0.091 moles

0.091 moles of nitrogen gas is contained in a container at STP.

6 0
3 years ago
Why glucose and fructose produce same shaped products with phenylhydrazine?
NemiM [27]

During the reaction of glucose and fructose with excess phenylhydrazine to form osazone, only the C-1andC-2 atoms of glucose and fructose participate in the reaction. The rest of the molecule remains intact. Hence, glucose and fructose produce the same osazone.

6 0
3 years ago
23.5 L of h2 is stored at a pressure of 58.7 Kpa what volume would the gas take up at stp
stepan [7]

Answer:-  13.6 L

Solution:- Volume of hydrogen gas at 58.7 Kpa is given as 23.5 L. It asks to calculate the volume of hydrogen gas at STP that is standard temperature and pressure. Since the problem does not talk about the original temperature so we would assume the constant temperature. So, it is Boyle's law.

Standard pressure is 1 atm that is 101.325 Kpa.

Boyle's law equation is:

P_1V_1=P_2V_2

From given information:-

P_1 = 58.7 Kpa

V_1 = 23.5 L

P_2 = 101.325 Kpa

V_2 = ?

Let's plug in the values and solve it for final volume.

58.7Kpa*23.5L=101.325Kpa*V_2

On rearranging the equation for V_2

V_2=\frac{58.7Kpa*23.5L}{101.325Kpa}

V_2 = 13.6 L

So, the volume of hydrogen gas at STP for the given information is 13.6 L.

3 0
3 years ago
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