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3 years ago

Tom read 20 books, 12 magazines, and 18 newspaper articles last year.

Mathematics

2 answers:

dezoksy [38]3 years ago

6 0

Answer:

24%

Step-by-step explanation:

the answer is 24% because all of the sources he read equal 50 you double that and that makes everything he read 2 % and since he read 12 magazines its 12 x 2 and thats 24%

Mamont248 [21]3 years ago

4 0

Answer:

24%

Step-by-step explanation:

12/50=24%

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Maya's chocolate bar is 29% cocoa. If the weight of the chocolate bar is 67 grams, how many grams of cocoa does it contain? Roun

nika2105 [10]

Answer:

Step-by-step explanation:

x/67=29/100

29x67=1943

1943/100=

19.43

Round:

8 0

2 years ago

Let X1, . . . ,Xn ∈ R be independent random variables with a common CDF F0. Let Fn be their ECDF and let F be any CDF. If F = Fn

Georgia [21]

Answer:

See the proof below.

Step-by-step explanation:

For this case we need to proof that: Let $X_1, X_2, ...X_n \in R$ be independent random variables with a common CDF $F_0$ . Let $F_n$ be their ECDF and let F any CDF. If $F \neq F_n$ then $L(F)$

Proof

Let $z_a$ different values in the set { $X_1,X_2,...,X_n}$ } and we can assume that $n_j \geq 1$ represent the number of $X_i$ that are equal to $z_j$ .

We can define $p_j = F(z_j) +F(z_j-)$ and assuming the probability $\hat p_j = \frac{n_j}{n}$ .

For the case when $p_j =0$ for any $j=1,....,m$ then we have that the $L(F) =0< L(F_n)$

And for the case when all $p_j >0$ and for at least one $p_j \neq \hat p_j$ we know that $log(x) \leq x-1$ for all the possible values $x>0$ . So then we can define the following ratio like this:

$log (\frac{L(F)}{L(F_n)}) = \sum_{j=1}^m n_j log (\frac{p_j}{\hat p_j})$

$log (\frac{L(F)}{L(F_n)}) = n \sum_{j=1}^m \hat p_j log(\frac{p_j}{\hat p_j})$

$log (\frac{L(F)}{L(F_n)}) < n\sum_{j=1}^m \hat p_j (\frac{p_j}{\hat p_j} -1)$

So then we have that:

$log (\frac{L(F)}{L(F_n)}) \leq 0$

And the log for a number is 0 or negative when the number is between 0 and 1, so then on this case we can ensure that $L(F) \leq L(F_n)$

And with that we complete the proof.

8 0

4 years ago

Solve equation a+6a-9=30

joja [24]

To solve any equation, we have to get the variables and the constants (numbers) on opposite sides of the equals sign.

First, we have to combine the like terms on the left side of the equation, resulting in

7a - 9 = 30

Then, because we want the constants on the right side of the equation, we have to +9 to cancel out the -9 on the left side.

7a=39

Next, the a has a coefficient of 7, which it is multiplied by. To undo multiplication, you have to divide. Therefore, we should divide both sides by 7.

a= 5 4/7 or 5.57142857143

In improper fraction form, a = 39/7, as this fraction cannot be simplified any farther.

3 0

3 years ago

A volume of a cylinder is given by the expression 6n2 – 13n – 28. The area of the base is 3n + 4.

olga nikolaevna [1]

Volume of cylinder = Base Area x Height

Height = Volume/Base

Height = (6n² -13n -28)/(3n+4)
Perform this division and you will get Height = 2n-7

9 0

3 years ago

Read 2 more answers

identify a two-digit dividend that will result in a quotient with a remainder 1 when the divisor is 4

Afina-wow [57]

17, 21, 25, etc. because when you divided 4 by any of these numbers you will get your answer with a remainder of 1. For example, 17/4 is 4 R.1 because 4 times 4 is 16, then you will have one left over. (At my school you always go to a decimal not a remainder)

3 0

4 years ago