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ipn [44]
2 years ago
6

What is 5 and 9 tenths times 1 and 9 tenths​

Mathematics
1 answer:
kykrilka [37]2 years ago
5 0

Answer:

11.21

Step-by-step explanation:

5.9*1.9

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Help help please i will mark u brill
Roman55 [17]

Answer:

Step-by-step explanation:

u/4 + 9.9 = 16.9

Putting value of u = 24 in the equation

24/4 + 9.9 = 16.9

6 + 9.9 = 16.9

15.9 = 16.9

Bringing like terms on one

16.9 - 15.9 = 1

7 0
2 years ago
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2x-8y=6<br> y=-7- x<br> what are the coordinates
goblinko [34]
2x-8(-7-x)=6
2x+56+8x=6
10x=-50
x=-5

y=-7-(-5)
y=-2

(-5,-2)
5 0
3 years ago
A certain shade of green paint is made from 5 parts yellow mixed with 3 parts blue. If 2 cans of yellow are used, how many cans
ad-work [718]

Answer:

1.2 cans

Step-by-step explanation:

5/3=1.6666667

2/1.2=1.6666667

4 0
3 years ago
In stage 2 of a rocket's takeoff, the speed of the rocket increases at a rate of 4.3% per minute. The speed of the rocket at the
Sveta_85 [38]

The correct option is:   B.  25000=5000(1.043)^t

<u><em>Explanation</em></u>

<u>The general form of growth equation</u> is:   A=P(1+r)^t , where A = final amount, P = initial amount, r = growth rate in decimal form and t = time duration

Here, the speed of the rocket at the beginning was 5,000 kilometers per hour and at the end will be 25,000 kilometers per hour. The speed increases at a rate of 4.3% per minute.

That means,  A= 25000 , P= 5000, r= 4.3\% = 0.043

Now <u>plugging these values into the above equation</u>, we will get......

25000=5000(1+0.043)^t\\ \\ 25000=5000(1.043)^t

So, the equation that could be used to determine the time for the speed of the rocket to reach 25,000 kilometers per hour will be:  25000=5000(1.043)^t

8 0
2 years ago
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0.135 written as a fraction is it <br><br> A.( 5 over 37<br> B.( 27 over 100<br> C. ( 27 over 200
Lady_Fox [76]

Answer:

idk


Step-by-step explanation:


4 0
2 years ago
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