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babunello [35]
3 years ago
12

Help plz if anybody know the answer

Mathematics
1 answer:
Tanzania [10]3 years ago
4 0

Answer: x^2+29x+39

You would first have to set up an equation, which would be ((2x+9)⋅(x+6))-((x-5)⋅(x-3)) to find the area of both rectangles.

Then you can simplify it, which gives us 2x^2+21x+54-(x^2-8x+15)

Then simplify it even more which gives us 2x^2+21x+54-x^2+8x-15

Then we can get our answer: x^2+29x+39

Hope that helps :)

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Solve for x: 4x - 8 = 7x - 2<br>Anyone know the answer for this one?<br>Thanks!​
erastovalidia [21]

Answer:

\huge{ \fbox{ \tt{x =  - 2}}}

Step-by-step explanation:

\underline{ \underline{ \mathfrak{Let's \: solve}}} :

\star{ \sf{ \:  \: 4x - 8 = 7x - 2}}

\text{Step \: 1} :  \sf{Move \: 7x \: to \: left \: hand \: side \: and \: change \: its \: sign}

\mapsto{ \sf{4x - 7x - 8 =  - 2}}

\text{Step \: 2} :  \sf{Move \: 8 \: to \: right \: hand \: side \: and \: change \: its \: sign}

\mapsto{ \sf{4x - 7x =  - 2 + 8}}

\text{Step \: 3} :  \sf{Collect \: like \: terms}

\sf{Like \: terms \: are \: those \: which \: have \: same \: base}

\mapsto{ \sf{ - 3x =  - 2 + 8}}

\text{Step \: 4} :  \sf{Calculate}

\underline{ \text{Remember!}} :  \sf{The \: negative \: and \: positive \: integers \: are \: always \: subtracted \: but \: posses \: the \: sign \: of \: the \: bigger \: integer.}

\mapsto{ \sf{ - 3x =  6}}

\text{Step \: 4} :  \sf{Divide \: both \: sides \: by \:  - 3}

\mapsto{ \sf{ \frac{ - 3x}{ - 3}  =  \frac{6}{ - 3}}}

\text{ Step \: 4} :  \sf{Calculate}

\mapsto{ \sf{x =  - 2}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

3 0
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Hope this helps!

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Step-by-step explanation:

2 ^ (4/3)

2^4 = 16

16 ^(1/3)

This is the cube root of 16

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