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sasho [114]

Answer:

wat

Explanation:

8 0

3 years ago

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Carbon dioxide gas enters a pipe at 3 MPa and 500 K at a rate of 2 kg/s. CO2 is cooled at constant pressure as it flows in the p

Viktor [21]

Answer:

a) 0.0629 $m^{3}/s$ ,ρ1=31.76 $kg/m^{3}$ ,0.05688 $m^{3}/s$

b) 0.06171 $m^{3}/s$ ,32.40966 $kg/m^{3}$ 0.05498 $m^{3}/s$

c) 0.004%

given data:

n=2 kg/s

R=188.92 J/kgK

$T_{1}$ =500 K

$T_{2}$ =450 K

solution:

a) as we know ideal gas relation

PV=nRT..........(1)

The volume flow rate of inlet is

$V_{1}= \frac{nRT_{1} }{P}$ ..................(2)

putting the value in eq(2)

$V_{1}$ =0.0629 $m^{3}/s$

to find destiny

ρ1= $\frac{n}{V_{1} }$ ...........................................(3)

putting value of n and V1 is eq 3

ρ1=31.76 $kg/m^{3}$

$V_{2} =\frac{nRT_{2} }{P}$ ............(A)

putting value in eq A

=0.05688 $m^{3}/s$

to find the rates from the compressibility factors we have to find the reduced pressure and temperature in both cases

P(reduced 1)= $\frac{P_{1} }{P_{crit} }$ = $\frac{3.10^{6} }{7.39 . 10^{6}}$ =0.41

T(reduced 1)= $\frac{T_{1} }{T_{crit} }$ = $\frac{500K}{304.25K}=1.64$

b) After looking at the chart we obtain $Z_{1}$ =0.98 now the volume flow rate at the inlet is:

$V_{1} =\frac{nRT_{1} Z_{1} }{P}$ ....................................................(4)

Putting the values in eq(4)

=0.06171 $m^{3}/s$

Now the density is

ρ= $\frac{n}{V_{1} }$

=32.40966 $kg/m^{3}$

now the reduced pressure and compressibility factor in second case will be

T(reduced 2)= $\frac{T_{2} }{T_{crit} }$ = $\frac{450}{304.25}$ =1.48

P(reduced 2)=P(reduced 1)=0.41

$Z_{2}$ =0.97

$V_{2} =\frac{nRT_{2} Z_{2} }{P}$ ............................................(5)

putting value in eq (5)

=0.05498 $m^{3}/s$

c) now find the error

Δn/n=modulus(ρ1 $V_{1}$ -n/n)*100%.....................(6)

putting the value in eq 6

=0.004%

6 0

3 years ago

When would working with machinery be a common type of caught-in and caught-between<br> hazard?

tigry1 [53]

Answer:

A working with machinery be a common type of caught-in and caught-between hazard is described below in complete detail.

Explanation:

“Caught in-between” accidents kill mechanics in a variety of techniques. These incorporate cave-ins and other hazards of tunneling activity; body parts extracted into unconscious machinery; reaching within the swing range of cranes and other installation material; caught between machine & fixed objects.

6 0

3 years ago

A service station has 10 employees who are responsible for checking in customers who bring their cars in to be serviced. The emp

stellarik [79]

Explanation:

for checking in customers who bring their cars in to be serviced. The employees are currently using legal pads to write down the customers’ information, the reason they need service, and identifying information about the car, such as the license plate number. Which wireless technology would help streamline the employees’ work duties and reduce errors from poor handwriting or lost/misplaced paper?

6 0

3 years ago

What are primary and secondary super-heaters?

Maru [420]

Explanation:

Superheater has two types of parts which are:

The primary super-heater
The secondary super-heater

Primary super-heater is first heater which is passed by the steam after steam comes out of steam drum.

After steam is heated on super primary heater, then the steam is passed on secondary super-heater so to be heated again. Thus, on secondary super-heater, the steam formed is hottest steam among others.

Steam from secondary super-heater which becomes the superheated steam, flow to rotate the High-Pressure Turbine.

3 0

3 years ago