During the collision, is the magnitude of the force of asteroid A on asteroid B greater than, less than, or equal to the magnitu
2 answers:
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Answer:
a) P ≥ 22.164 Kips
b) Q = 5.4 Kips
Explanation:
GIven
W = 18 Kips
μ₁ = 0.30
μ₂ = 0.60
a) P = ?
We get F₁ and F₂ as follows:
F₁ = μ₁*W = 0.30*18 Kips = 5.4 Kips
F₂ = μ₂*Nef = 0.6*Nef
Then, we apply
∑Fy = 0 (+↑)
Nef*Cos 12º - F₂*Sin 12º = W
⇒ Nef*Cos 12º - (0.6*Nef)*Sin 12º = 18
⇒ Nef = 21.09 Kips
Wedge moves if
P ≥ F₁ + F₂*Cos 12º + Nef*Sin 12º
⇒ P ≥ 5.4 Kips + 0.6*21.09 Kips*Cos 12º + 21.09 Kips*Sin 12º
⇒ P ≥ 22.164 Kips
b) For the static equilibrium of base plate
Q = F₁ = 5.4 Kips
We can see the pic shown in order to understand the question.
Solution:
Given that :
Volume flow is,
So,
Therefore, the equation of a single straight vessel is given by
......................(i)
So there are 100 similar parallel pipes of the same cross section. Therefore, the equation for the area is
or
Now for parallel pipes
...........(ii)
Solving the equations (i) and (ii),
Therefore,
or
Thus the answer is option A). 10
Answer:
a. Using a straight forward scheme, the RC4 algorithm stores 2064 bits in the interval state.
b. 1700 bits
Explanation:
See RC4 Algorithm attached with details
