Answer:
Answer for the question is : Solidification time will be same i.e. 170. See attached file for explanation.
Explanation:
The professional ethics for computer engineers are:
- They will Contribute to society and to human well-being.
- They will Avoid harm.
- Be honest and trustworthy.
- They will be fair and take action that do to discriminate others.
<h3>What are the Characteristics of Code of Ethics?</h3>
The code of ethics are known to be a kind of a universal moral values, that is one that state that what a person expect of any given employee such as been trustworthy, respectful, responsible, and others.
Note that Rules of Practice, Professional Obligations and Codes of Ethics. are known to be put in place to avoid issues that may lead to conflict.
Therefore, i believe that As Engineering and Computing students, the respective professional bodies, Rules of Practice, Professional Obligations and Codes of Ethics are good and acts as a check and balance to us.
Therefore, The professional ethics for computer engineers are:
- They will Contribute to society and to human well-being.
- They will Avoid harm.
- Be honest and trustworthy.
- They will be fair and take action that do to discriminate others.
Learn more about Engineering rules from
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Answer:
Explanation:
4140-40 I’d pick wood
I hope this helps! :)
Answer:
a) it is periodic
N = (20/3)k = 20 { for K =3}
b) it is Non-Periodic.
N = ∞
c) x(n) is periodic
N = LCM ( 5, 20 )
Explanation:
We know that In Discrete time system, complex exponentials and sinusoidal signals are periodic only when ( 2π/w₀) ratio is a rational number.
then the period of the signal is given as
N = ( 2π/w₀)K
k is least integer for which N is also integer
Now, if x(n) = x1(n) + x2(n) and if x1(n) and x2(n) are periodic then x(n) will also be periodic; given N = LCM of N1 and N2
now
a) cos(2π(0.15)n)
w₀ = 2π(0.15)
Now, 2π/w₀ = 2π/2π(0.15) = 1/(0.15) = 1×20 / ( 0.15×20) = 20/3
so, it is periodic
N = (20/3)k = 20 { for K =3}
b) cos(2n);
w₀ = 2
Now, 2π/w₀ = 2π/2) = π
so, it is Non-Periodic.
N = ∞
c) cos(π0.3n) + cos(π0.4n)
x(n) = x1(n) + x2(n)
x1(n) = cos(π0.3n)
x2(n) = cos(π0.4n)
so
w₀ = π0.3
2π/w₀ = 2π/π0.3 = 2/0.3 = ( 2×10)/(0.3×10) = 20/3
∴ N1 = 20
AND
w₀ = π0.4
2π/w₀ = 2π/π0. = 2/0.4 = ( 2×10)/(0.4×10) = 20/4 = 5
∴ N² = 5
so, x(n) is periodic
N = LCM ( 5, 20 )
