What is the remainder when 7x^2- x^3is divided by x - 8?

Mathematics

1 answer:

White raven [17]2 years ago

3 0

Answer:

The remainder is -64

Step-by-step explanation:

Given

$7x^2 - x^3$

Divided by $x - 8$

Required

Determine the remainder

Equate $x - 8$ to 0

$x - 8 = 0$

Solve for x

$x = 8$

Using remainder theorem, substitute 8 for x in $7x^2 - x^3$

So, we have:

$7 * 8^2 - 8^3$

Evaluate all exponents

$7 * 64 - 512$

$448 - 512$

$-64$

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8.23 A manufacturing company produces electric insulators. You define the variable of interest as the strength of the insulators

Kitty [74]

Answer:

The 95% confidence interval estimate for the population mean force is (1691, 1755).

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally.

The sample selected here is <em>n</em> = 30.

Thus, the sampling distribution of the sample mean will be normal.

Compute the sample mean and standard deviation as follows:

$\bar x=\frac{1}{n}\sum x=\frac{1}{30}\times 51702=1723.4\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{30-1}\times 232561.2}=89.55$