The density is defined as mass of a substance per unit of its volume
It can be expressed in different units like g/L g/m3 Kg/dm3 etc
We are given that
mass of substance = 27.3 grams
volume of substance = 7 cm^3
the density = Mass of substance / volume of substance
density = 27.3g / 7 cm^3 = 3.9 g /cm^3
The above question is incomplete, here is the complete question:
Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:
Answer:
The standard molar enthalpy of formation of NO is 90.25 kJ/mol.
Explanation:
To calculate the standard molar enthalpy of formation
...[3]
Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
[1] - [2] = [3]
According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :
=
Answer:
the iupac name of CH3-CH2-CH2-OH Propanol.
We have to distinguish a solution of sodium sulphite from a solution of sodium sulphate in the laboratory.
Solution of sodium sulphite is acidified with dilute HCl and to that when few drops of barium chloride (BaCl₂) solution is added, white precipitate is formed. The white precipitate is soluble in HCl.
To this solution 2 drops of iodine (I₂) solution is added and brown colour of iodine is discharged as I₂ gets reduced to HI.
The reactions involved in case of sodium sulphite is are:
Na₂SO₃ + BaCl₂ = BaSO₃ ↓ + 2NaCl
(white precipitate)
BaSO₃ + 2HCl = BaCl₂ + H₂SO₃
H₂SO₃ + I₂ + H₂O = H₂SO₄ + 2HI
On the other hand, solution of sodium sulphate is acidified with dilute HCl and to that when few drops of barium chloride (BaCl₂) solution is added, white precipitate is formed. The white precipitate of BaSO₄ is formed which is insoluble in HCl.
Na₂SO₄+ BaCl₂ = BaSO₄ ↓ + 2NaCl
(white precipitate)