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Bingel [31]
3 years ago
7

How many moles are in 153 grams of O2?

Chemistry
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

4.78 mol O2

Explanation:

Grams --> moles

Grams/molar mass = moles

153 g O2 / 32 g/mol O2 = 4.78125 (significant figures so round it up; the grams has 3 significant figures, so round it up) 4.78 mol O2

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Aspirin synthesis involves the addition of an acetyl group to salicylic acid in a condensation reaction with an alcohol. The ace
BARSIC [14]

Answer:

The correct appropriate will be Option 1 (Acid anhydrides are less stable than esters so the equilibrium favors the ester product.)

Explanation:

  • Acid anhydride, instead of just a carboxyl group, is typically favored for esterification. The predominant theory would be that Anhydride acid is somewhat more volatile than acid. This is favored equilibrium changes more toward the right of the whole ester structure.
  • Extremely responsive than carboxylic acid become acid anhydride as well as acyl chloride. Thus, for esterification, individuals were most favored.

The other options offered are not relevant to something like the scenario presented. So, the solution here is just the right one.

3 0
3 years ago
Identify what type of reaction is below. Also determine what coefficients that would balance the chemical equation.
pantera1 [17]

Answer:

4HCl + 2Zn = 2H2 + 2ZnCl2

I hope it's helps you

3 0
3 years ago
How many grams of magnesium acetate are in 8.95x10^23 formula units?
Natasha_Volkova [10]

Answer:

211.63 g.

Explanation:

  • Particles could refer to atoms, molecules, formula units.
  • <em>Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).</em>

<em><u>Using cross multiplication:  </u></em>

1.0 mole → 6.022 x 10²³ molecules.

??? mole → 8.95 x 10²³ molecules.

  • The no. of moles of magnesium acetate = (8.95 x 10²³ molecules) (1.0 mole) / (6.022 x 10²³ molecules) = 1.486 mol.

∴ The grams of magnesium acetate are in 8.95 x 10²³ formula units = n x molar mass = (1.486 mol)(142.394 g/mol) = 211.63 g.

5 0
3 years ago
A student determines that 23.1 J of heat are required to raise the temperature of 6.67 g of an
Semenov [28]

A student determines that 23.1 J of heat are required to raise the temperature of 6.67 g of an

5 0
2 years ago
6. Calculate the molarity if 35.0 grams of KBr are dissolved in 700. ml?
olga55 [171]

Answer:

To calculate molarity, divide the number of moles of solute by the volume of the solution in liters. If you don't know the number of moles of solute but you know the mass, start by finding the molar mass of the solute, which is equal to all of the molar masses of each element in the solution added together.

Explanation:

try starting with 35.0 and dived it by the volume

8 0
3 years ago
Read 2 more answers
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