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3 years ago

2C3H7OH + 9O2 --> 6CO2 + 8H2O

Chemistry

1 answer:

Ne4ueva [31]3 years ago

8 0

<h3>Answer:</h3>

733 g CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O

[Given] 5.55 mol C₃H₇OH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol C₃H₇OH → 6 CO₂

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Stoichiometry</u>

Set up conversion: $\displaystyle 5.55 \ mol \ C_3H_7OH(\frac{6 \ mol \ CO_2}{2 \ mol \ C_3H_7OH})(\frac{44.01 \ g \ CO_2}{1 \ mol \ CO_2})$
Multiply/Divide: $\displaystyle 732.767 \ g \ CO_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

732.767 g CO₂ ≈ 733 g CO₂

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Answer:

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Explanation:

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steposvetlana [31]

Answer:

Answer : The correct answer for mass of KBr = 2.53 g

Given :

Molarity of KBr solution = 0.85 M

Volume of KBr solution = 25 mL

Converting volume from mL to L ( 1 L = 1000 mL )

Volume of solution = 25 mL * \frac{1 L }{1000mL}Volumeofsolution=25mL∗

1000mL

Volume of solution = 0.025 L

Mass of KBr = ?

Mass of KBr can be calculated using following steps :

1) To find mole of Kbr :

Mole of KBr can be calculated using molarity .

Molarity : It is defined as mole of solute present in volume of solution in Liter .

It uses unit as M or \frac{mol}{L}

mol

It can be expressed as :

Molarity = \frac{mol of solute (mol)}{volume of solution (L)}Molarity=

volumeofsolution(L)

molofsolute(mol)

Plugging value of molarity and volume

0.85 \frac{mol}{L} = \frac{mol of Kbr}{0.025 L}0.85

mol

0.025L

molofKbr

Multiplying both side by 0.025 L

0.85 \frac{mol}{L} * 0.025 L = \frac{mole of KBr}{0.025 L} * 0.025 L0.85

mol

∗0.025L=

0.025L

moleofKBr

∗0.025L

Mole of KBr = 0.02125

2) To find mass of Kbr :

Mass of Kbr can be calculated using mole . Mole can be expressed as :

Mole (mol) = \frac{mass (g) }{molar mass \frac{g}{mol} }Mole(mol)=

molarmass

mol

mass(g)

Mole of Kbr = 0.02125 mol

Molar mass of KBr = 119.00 \frac{g}{mol}

mol

Plugging values in mole formula

0.02125 mol = \frac{mass (g)}{119.00 \frac{g}{mol}}0.02125mol=

119.00

mol

mass(g)

Multiplying both side by 119.00 \frac{g}{mol}

mol

0.02125 mol * 119.00 \frac{g}{mol} = \frac{mass (g)}{119.00 \frac{g}{mol}} * 119.00\frac{g}{mol}0.02125mol∗119.00

mol

119.00

mol

mass(g)

∗119.00

mol

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