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LUCKY_DIMON [66]
3 years ago
14

Which equation correctly represents the electron affinity of the cesium atom? Cs (g) Cs1 (g)+2 e Cs+1 (g) Cs (g) + 1e Cs (g) OCs

+1 (g) +1e Cs1 (g) Cs (g) +1e Cs (g) Cs1 (g) + 1e
Chemistry
2 answers:
ira [324]3 years ago
6 0

Answer:

Cs+(g)+1e^- Cs(g)

DENIUS [597]3 years ago
4 0

Answer : The correction equation will be:

Cs^+(g)+1e^-\rightarrow Cs(g)

Explanation :

Electron affinity : It is defined as the addition of electron to the atom or to the ion. The atom or ion is always in gaseous phase.

In other words we can say that, the gaining of electrons is said to be an electron affinity.

As, the given element is a metal given in cationic form, so its positive ion will gain an electron to form a neutral atom.

The balanced and correct equation for electron affinity of the cesium ion will be:

Cs^+(g)+1e^-\rightarrow Cs(g)

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A copper cylinder, 12.0 cm in radius, is 44.0 cm long. If the density of commoner is 8.90 g/cm3, calculate the mass in grams of
inna [77]

The mass of the copper cylinder is 177065.856g

Given:

Radius of the copper cylinder R=12cm

Height of the copper cylinder H=44cm

Density of the cylinder=8.90 \frac{g}{c m^{3}}

To find:

Mass of the copper cylinder

<u>Step by Step by explanation:</u>

Solution:

According to the formula, Mass can be calculated as

\rho=\frac{m}{v} and from this

m=\rho \times v

Where, m=mass of the cylinder

\rho =density of the cylinder

v=volume of the cylinder

And also cylinder is provided with radius and height value.

So volume of the cylinder is calculated as

v=\pi r^{2} h

Where \pi=3.14

r=radius of the cylinder=12cm

h=height of the cylinder=44cm

Thus, v=3.14 \times 12^{2} \times 44

v=3.14 \times 144 \times 44

v=19895.04 \mathrm{cm}^{3}

And we know that, m=\rho \times v

Substitute the known values in the above equation we get

m=8.90 \times 19895.04  

m=177065.856g or 177.065kg

Result:

Thus the mass of the copper cylinder is 177065.856g

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