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andreyandreev [35.5K]
3 years ago
12

What is the wavelength of a 1200 Hz sound wave?

Physics
1 answer:
blagie [28]3 years ago
3 0

Answer:

50cm

Explanation:

im honestly guessing

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A cart is set up as shown below, with three fans directed to the left and two of the fans running. The motion of the cart is rep
sasho [114]
The force of 3 fans would be grater than the force of 2 fans. 
So the cart would have greater acceleration to the right, and
it would reach a greater speed to the right.  The resulting
'v' vs 't' graph would have a greater positive slope, and would
be higher at any given time.

You might get a better answer if you let us actually SEE the
picture and the graph.
5 0
4 years ago
Read 2 more answers
Guys I really need help with these 2 questions , it's for my final plz help asap
mars1129 [50]

Answer:

(1) Initial speed, u=0

    Final speed, v=165.76m/s

    Average speed, v_a_v_g=82.87m/s

(2) Force of gravity, F_g=12.8\times10^1^5N

Explanation:

(1)

Given,

Distance, S=300meter

Time, t=3.62second

It is given that drag racer started at rest.

So Initial speed, u=0

Using Newton's second equation of motion,

S=ut+\frac{1}{2}at^2\\300=0+\frac{a\times3.62^2}{2} \\a=45.79m/s^2

Newton's first equation of motion,

v=u+at\\=0+45.79\times3.62\\=165.76 m/s

So, Final speed, v=165.76m/s

Average speed is defined as totle distance divided by totle time.

v_a_v_g=\frac{S}{t}\\=\frac{300}{3.62} \\=82.87m/s

So, Average speed, v_a_v_g=82.87m/s

(2)

Gravitation: It is the natural phenomenon in which two different bodies attract each other by virtue of their masses.

       According to Newton's law of gravitation, the force of attraction between two bodies is directly proportional to the masses of the bodies and inversely proportional to square of distance between centers of mass of the bodies.

                         F_g\propto\frac{m_1m_2}{r^2} \\F_g=G\frac{m_1m_2}{r^2}where Gis constant of proportionality and known as gravitation constant.

Given,

Mass of Jupiter, m_1=1.9\times10^2^7kg

Mass of Ganymede, m_2=1.48\times10^2^3kg

Distance between their centers of mass, r=1.21\times10^1^2meter

F_g=G\frac{m_1m_2}{r^2}\\=\frac{6.67\times10^-^1^1\times1.9\times10^2^7\times1.48\times10^2^3}{(1.21\times10^1^2)^2} \\=12.8\times10^1^5N

So, Force of gravity, F_g=12.8\times10^1^5N

7 0
3 years ago
An object moves along the grid through the points A, B, C, D, E, and Fas shown below.
sveticcg [70]

Answer:

Total distance = 6.5 km

Explanation:

Let the distance be denoted by the vectors drawn from A, B, C, D, E, and F.

Then the distance covered can be calculated by adding the vectors in the direction given.

Total distance = 3km + 1km+ 1.5km+ 0.5km+ 0.5km

Total distance = 6.5 km

If we were to find the displacement ( shortest distance) then the head to tail rule would be applied using the vectors.

7 0
3 years ago
What might happen if transformers didn’t exist?
Karolina [17]

Answer:

B electricity could not be distributed through power lines to people's homes

7 0
3 years ago
A car moves along an x axis through a distance of 900 m, starting at rest (at x = 0) and ending at
OlgaM077 [116]
A car moves along an x axis through a distance of 900 m, starting at rest (at x = 0) and ending at rest (at x = 900 m). Through the first 1/4 of that distance, its acceleration is +6.25 m/s2. Through the next 3/4 of that distance, its acceleration is -2.08 m/s2. What are (a) its travel time through the 900 m and (b) its maximum speed? 

<span>Solve for the time at the 1/4 mark. That's 225 m. How? d = (1/2)at^2 ( initial velocity zero). Thus 225 = (1/2) 6.25 t^2. t^2 = ( 225 * 2 ) / 6.25. t = 8.5 sec. </span>

<span>At the other end t^2 = (675 * 2) / 2.08 -- we reversed the sign and ran time backwards. t = 25.5 sec. </span>

<span>So total time is 8.5 + 25.5 or 34 sec. </span>

<span>Since zero initial velocity: v^2 = 2 a d. Here, v^2 = 2 * 6.25 * 225. v = 53 m/s. That's the fastest speed since braking then occurs.</span>
7 0
4 years ago
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