The force of 3 fans would be grater than the force of 2 fans.
So the cart would have greater acceleration to the right, and
it would reach a greater speed to the right. The resulting
'v' vs 't' graph would have a greater positive slope, and would
be higher at any given time.
You might get a better answer if you let us actually SEE the
picture and the graph.
Answer:
(1) Initial speed, 
Final speed, 
Average speed, 
(2) Force of gravity, 
Explanation:
(1)
Given,
Distance, 
Time, 
It is given that drag racer started at rest.
So Initial speed,
Using Newton's second equation of motion,
Newton's first equation of motion,
So, Final speed,
Average speed is defined as totle distance divided by totle time.
So, Average speed,
(2)
Gravitation: It is the natural phenomenon in which two different bodies attract each other by virtue of their masses.
According to Newton's law of gravitation, the force of attraction between two bodies is directly proportional to the masses of the bodies and inversely proportional to square of distance between centers of mass of the bodies.
where 
is constant of proportionality and known as gravitation constant.
Given,
Mass of Jupiter, 
Mass of Ganymede, 
Distance between their centers of mass, 
So, Force of gravity,
Answer:
Total distance = 6.5 km
Explanation:
Let the distance be denoted by the vectors drawn from A, B, C, D, E, and F.
Then the distance covered can be calculated by adding the vectors in the direction given.
Total distance = 3km + 1km+ 1.5km+ 0.5km+ 0.5km
Total distance = 6.5 km
If we were to find the displacement ( shortest distance) then the head to tail rule would be applied using the vectors.
Answer:
B electricity could not be distributed through power lines to people's homes
A car moves along an x axis through a distance of 900 m, starting at rest (at x = 0) and ending at rest (at x = 900 m). Through the first 1/4 of that distance, its acceleration is +6.25 m/s2. Through the next 3/4 of that distance, its acceleration is -2.08 m/s2. What are (a) its travel time through the 900 m and (b) its maximum speed?
<span>Solve for the time at the 1/4 mark. That's 225 m. How? d = (1/2)at^2 ( initial velocity zero). Thus 225 = (1/2) 6.25 t^2. t^2 = ( 225 * 2 ) / 6.25. t = 8.5 sec. </span>
<span>At the other end t^2 = (675 * 2) / 2.08 -- we reversed the sign and ran time backwards. t = 25.5 sec. </span>
<span>So total time is 8.5 + 25.5 or 34 sec. </span>
<span>Since zero initial velocity: v^2 = 2 a d. Here, v^2 = 2 * 6.25 * 225. v = 53 m/s. That's the fastest speed since braking then occurs.</span>
