Given: Mass m= 10 g convert to Kg m = 0.01 Kg Velocity V = 300 m/s
Required: Kinetic energy = K.E = 1/2 mV²
K.E = 1/2 (0.01 Kg)(300 m/s)²
K.E = 450 J
You can describe kinetic energy and the potential energy of motion to get your answer.
I believe its the third answer
Answer:
0.0816 kgm/s
Explanation:
From the question,
Momentum of the pellet just before it hits the modelling clay is = (mass of the pellet+ mass of the truck clay)×initial velocity of pellet.
P =(M+m)u...................... Equation 1
Where P = initial momentum of the pellet, m = mass of the pellet, u = initial speed of the pillet, M = mass of the truck
Given: m = 2 g = 2/1000 kg = 0.002 kg, u = 0.8 m/s, M = 0.1 kg
Substitute these values into equation 1
P = (0.002+0.1)0.8
P = (0.102)0.8
P = 0.0816 kgm/s
The answer is D. The input force is equal to the output force.
I just did test and got it right
