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lyudmila [28]
3 years ago
10

An infinitely large plane carries a uniformly distributed charge such that the charge per unit area is 3.47E-6 C/m2. What is the

electric field magnitude |E| at a point that is 2.40 m from the plane
Physics
1 answer:
kodGreya [7K]3 years ago
3 0

Answer:1.95\times 10^5\ N/C

Explanation:

Given

The charge per unit area on the plate is \sigma =3.47\times 10^{-6}\ C/m^2

Electric for a infinitely large plane is given by

E=\dfrac{\sigma }{2\epsilon_o}

Therefore, electric field at a point 2.4 m from the plane is

\Rightarrow E=\dfrac{3.47\times 10^{-6}}{2\times 8.854\times 10^{-12}}\\\\\Rightarrow E=0.195\times 10^6\ N/C

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Alex

Answer:

H_w = 2.129 m

Explanation:

given,

Width of the weir, B = 1.2 m

Depth of the upstream weir, y = 2.5 m

Discharge, Q = 0.5 m³/s

Weir coefficient, C_w = 1.84 m

Now, calculating the water head over the weir

Q = C_w BH^{3/2}

H = (\dfrac{Q}{C_wB})^{2/3}

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H = 0.371\ m

now, level of weir on the channel

H_w = y - H

H_w = 2.5 - 0.371

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Height at which weir should place is equal to 2.129 m.

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4 years ago
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Answer:

8 times

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If during exercise it can pump 40 quarts per minute, that is, 80 quarts in 2 minutes.

To know how many times does all of your blood complete the cycle around your body during exercise, you must divide 80 quarts by 10 quarts. That is,

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<span>As a car drives with its tires rolling freely without any slippage, the type of friction acting between the tires and the road is kinetic friction.

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Answer:

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