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Thepotemich [5.8K]
2 years ago
11

Please help, I'll give 5 stars and brainliest!

Chemistry
2 answers:
Bezzdna [24]2 years ago
8 0
Huh. Is this supposed to be biology?
anastassius [24]2 years ago
4 0
1. Potential
2. Gravity and weigh and height
3. Stretched
4. Elastic potential energy and stored
5. Chemical energy first then thermal energy
I don’t know if this is actually all correct but I tried my best
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What is the empirical formula for a compound that is 94.1% oxygen and 5.90 % hydrogen?
RSB [31]

Answer:

The empirical formula would be N₂Os * Page 2 Calculate the empirical formulaof a compound that is 94.1% oxygen, 5.9% hydrogen.

6 0
3 years ago
Is the combustion of gasoline endothermic or exothermic?
UNO [17]
The reaction would be Exothermic
5 0
3 years ago
A 41.1 g sample of solid CO2 (dry ice) is added to a container at a temperature of 100 K with a volume of 3.4 L.A. If the contai
marta [7]

Answer:

Approximately 6.81 × 10⁵ Pa.

Assumption: carbon dioxide behaves like an ideal gas.

Explanation:

Look up the relative atomic mass of carbon and oxygen on a modern periodic table:

  • C: 12.011;
  • O: 15.999.

Calculate the molar mass of carbon dioxide \rm CO_2:

M\!\left(\mathrm{CO_2}\right) = 12.011 + 2\times 15.999 = 44.009\; \rm g \cdot mol^{-1}.

Find the number of moles of molecules in that 41.1\;\rm g sample of \rm CO_2:

n = \dfrac{m}{M} = \dfrac{41.1}{44.009} \approx 0.933900\; \rm mol.

If carbon dioxide behaves like an ideal gas, it should satisfy the ideal gas equation when it is inside a container:

P \cdot V = n \cdot R \cdot T,

where

  • P is the pressure inside the container.
  • V is the volume of the container.
  • n is the number of moles of particles (molecules, or atoms in case of noble gases) in the gas.
  • R is the ideal gas constant.
  • T is the absolute temperature of the gas.

Rearrange the equation to find an expression for P, the pressure inside the container.

\displaystyle P = \frac{n \cdot R \cdot T}{V}.

Look up the ideal gas constant in the appropriate units.

R = 8.314 \times 10^3\; \rm L \cdot Pa \cdot K^{-1} \cdot mol^{-1}.

Evaluate the expression for P:

\begin{aligned} P &=\rm \frac{0.933900\; mol \times 8.314 \times 10^3 \; L \cdot Pa \cdot K^{-1} \cdot mol^{-1} \times 298\; K}{3.4\; L} \cr &\approx \rm 6.81\times 10^5\; Pa \end{aligned}.

Apply dimensional analysis to verify the unit of pressure.

4 0
3 years ago
50 POINTS PLEASE HELP!
Aleks04 [339]

Answer: The molar mass of the gas is 9.878 g/mol.

Explanation:

According to Graham's law, the rate of diffusion is inversely proportional to square root of molar mass of gas.

Rate = \frac{1}{\sqrt{M}}

where,

M = molar mass of gas

As given gas diffuses 1/7 times faster than hydrogen gas. So, its molar mass is calculated as follows.

\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\

where,

M_{1} = molar mass of hydrogen gas

M_{2} = molar mass of another given gas

R_{1} = rate of diffusion of hydrogen

R_{2} = rate of diffusion of another given gas = \frac{1}{7}R_{1}

Substitute the values into above formula as follows.

\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\\frac{R_{1}}{\frac{1}{7}R_{1}} =  \sqrt{\frac{M_{2}}{2}}\\7 \times 1.414 = M_{2}\\M_{2} = 9.878 g/mol

Thus, we can conclude that the molar mass of the gas is 9.878 g/mol.

7 0
3 years ago
Read 2 more answers
Plzzz helpp mee easapp ndjjs
klemol [59]
I think it is with screens l, chemicals, and filters
I hope this helped
4 0
2 years ago
Read 2 more answers
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