Answer:
gde
Explanation:
We are attempting to synthesize 1-butyne from 1-chlorobutane. Since 1-chlorobutane is a primary alkyl halide, 1-butene is formed when 1-chlorobutane is reacted with a bulky base such as t -BuOK or t -BuOH in presence of strong heat. This is an E2 reaction.
Secondly, the 1-butene is reacted with bromine in carbon tetrachloride. The vicinal dihalide (1,2-dibromobutane) is formed. This can now undergo further elimination reactions in the presence of sodamide and strong heat to yield 1-butyne which is the desired product. These reactions involve the elimination of the first HBr molecule to give an alkenyl bromide. A second elimination now gives the terminal alkyne.
Answer:
Americium is: [Rn]5f^7s^2
Bismuth is: [Xe]6s^24f^145d^106p^3
Tin is: [Kr]4d^105s^25p^2
Vanadium is: [Ar]3d^34s^2
Aluminum is [Ne]3s^23p^1
Answer:
An equal force acts in the opposite direction.
Explanation:
The answer that h are looking for is c
