2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)
Explanation:
Balanced chemical equation for combustion of pentane C₅H₁₀:
C₅H₁₀ (l) + (15/2) O₂ (g) → 5 CO₂ (g) + 5 H₂O (g)
to get integer numbers for the stoechiometric coefficients we multiply with 2:
2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)
where:
(l) - liquid
(g) - gas
Learn more about:
combustion of hydrocarbons
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The answer to this question is C, I hope this helps you!
<h2><u>Answer:</u></h2>
So as to picture this, we should think about the situation of electrons in the obligations of benzene. This sort of structure is known as a reverberation mixture of the benzene particle. Actually, neither structure truly exists. Delocalisation must be clarified utilizing a larger amount of hypothesis than single and twofold bonds.
Reverberation of Benzene. The swaying twofold bonds in the benzene ring are clarified with the assistance of reverberation structures according to valence bond hypothesis. All the carbon iotas in the benzene ring are sp2 hybridized.
