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2 years ago

What is the molecular formula of a component whose molar mass is 88.0 and whose percent composted is 9.1

Chemistry

1 answer:

Shalnov [3]2 years ago

4 0

The molecular formula : C₄H₈O₂

<h3>Further explanation</h3>

Maybe a compound is 54.5% carbon, 9.1% hydrogen and 36.4% oxygen,so :

mol C :

$\tt \dfrac{54.5}{12}=4.54$

mol H :

$\tt \dfrac{9.1}{1}=9.1$

mol O :

$\tt \dfrac{36.4}{16}=2.28$

Divide by 2.28(the smallest ratio) :

C H : O =

$\tt \dfrac{4.54}{2.28}\div \dfrac{9.1}{2.28}\div \dfrac{2.28}{2.28}=2\div 4\div 1$

The empirical formula : C₂H₄O

(The empirical formula)n=molecular formula

(2.12+4.1+16)n=88

(44)n=88⇒n=2

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11.9 g Cl2 is reacted with 10.7 g NaOH. How many moles of NaCl are produced?

melisa1 [442]

Answer:

1. 7.256g of NaCl

2. 47.33g of Cl2

Explanation:

2 moles of Na reacts to produce 2 moles of NaCl

8 moles of Na will still produce 8 moles of NaCl

Mass of NaCl = molar mass of Nacl/moles of Nacl

=58.5/8

=7.256g of NaCl

From the equation, 2 moles of Na reacts with 1 mole of Cl2

3/2 moles of Cl2 will react with 3 moles of Na

Mass of Cl2 = 71/1.5

=47.33g of Cl2

Explanation:

4 0

2 years ago

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate

vovangra [49]

Answer:

K2 = 61.2 M^-1.S^-1

Explanation:

We complete the question fully:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0kJ/mol . If the rate constant of this reaction is 6.7M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

Answer is as follows:

The question asks us to calculate the value of the rate constant at a certain temperature, given that it is at a particular value for a particular temperature. We solve the question as follows:

According to Arrhenius equation, the relationship between temperature and activation energy is as follows:

k = Ae^-(Ea/RT)

where, k = rate constant

A = pre-exponential factor

Ea = activation energy

R = gas constant

T = temperature in kelvin

From the equation, the following was derived for a double temperature problem:

ln(k2/k1) = (-Ea/R) * (1/T1 - 1/T2)

We list out the parameters as follows:

T1= (244 + 273.15) K = 517.15 K

T2= (324+ 273.15) K =597.15 K

K1 = 6.7 , K2 = ?

R = 8.314 J/mol K

Ea = 71.0 kJ/mol = 71000 J/mol

Putting the given values into the above formula as follows:

ln(k2/6.7) = (-71000/8.314) * (1/517.15 - 1/597.15)

lnk2 - 1.902 = 8539.8 * 0.000259

lnK2 = 1.902 + 2.21

lnK2 = 4.114

K2 = e^(4.114)

K2 = 61.2

Hence, K2 = 61.2 (M.S)^-1

7 0

2 years ago

Read 2 more answers

Which type of orbital will be occupied by the electrons of highest energy for the Si^4+ ground-state ion? 1. 2s 2. 3p 3. 4s 4. 4

Shtirlitz [24]

Answer: Option (5) is the correct answer.

Explanation:

It is known that the ground state electronic configuration of silicon is $[Ne]3s^{2}3p^{2}$ .

And, we know that when an atom tends to gain an electron then it acquires a negative charge and when an atom tends to lose an electron then it acquires a positive charge.

As $Si^{4+}$ has a +4 charge which means that it has lost 4 electrons. Hence, the electronic configuration of $Si^{4+}$ is $1s^{2}2s^{2}2p^{6}$ .

According to the Aufbau principle, in the ground state of an atom or ion the electrons fill atomic orbitals of the lowest energy levels first, before filling the higher energy levels.

As 2p orbital is filled after the filling of 2s orbital.

Therefore, we can conclude that 2p orbital will be occupied by the electrons of highest energy for the $Si^{4+}$ ground-state ion.

4 0

2 years ago

73g of HCL in 2.00l of HCL solution

Whitepunk [10]

What is your question?

8 0

2 years ago

890J of heat are applied to a piece of aluminum, causing a 4.6°C increase in its temperature. The specific heat of aluminum is 0

Semmy [17]

Answer:

The answer would be C 214g

Explanation:

890j of heat causes 4.6°c increase in temperature

specific heat of aluminium after is o.9022 j /g°c

now by using the formula .The mass of aluminium would be c that is 214 g

7 0

2 years ago