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Elena L [17]
3 years ago
10

What is the molecular formula of a component whose molar mass is 88.0 and whose percent composted is 9.1

Chemistry
1 answer:
Shalnov [3]3 years ago
4 0

The molecular formula : C₄H₈O₂

<h3>Further explanation</h3>

Maybe a compound is 54.5% carbon, 9.1% hydrogen and 36.4% oxygen,so :

mol C :

\tt \dfrac{54.5}{12}=4.54

mol H :

\tt \dfrac{9.1}{1}=9.1

mol O :

\tt \dfrac{36.4}{16}=2.28

Divide by 2.28(the smallest ratio) :

C H : O =

\tt \dfrac{4.54}{2.28}\div \dfrac{9.1}{2.28}\div \dfrac{2.28}{2.28}=2\div 4\div 1

The empirical formula : C₂H₄O

(The empirical formula)n=molecular formula

(2.12+4.1+16)n=88

(44)n=88⇒n=2

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Answer: 12.78ml

Explanation:

Given that:

Volume of KOH Vb = ?

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