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nydimaria [60]
3 years ago
8

Will mark brainliest, please answer:)

Mathematics
1 answer:
yanalaym [24]3 years ago
7 0

Check the picture below.

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Solve for b<br> 2(-2b+3)=9
Alexxx [7]

Answer:

b=-3/4 or b=-0.75

Step-by-step explanation:

2(-2b+3)=9

2b+3=\cfrac{9}{2}

-2b=\cfrac{9}{3} -3

-2b=\cfrac{3}{2}

b=-\cfrac{\frac{3}{2} }{2}

b=-\cfrac{3}{2\times 2}

b=-\cfrac{3}{4}

Hope it helps! :)

7 0
2 years ago
Determine how long it will take an object to rotate through 6.9 revolutions at an angular velocity of 3.1 radians per second. Us
gregori [183]

Answer: 13 . 99 seconds

Step-by-step explanation:

The formula to find how long it will take an object to rotate through 6.9 revolutions at an angular velocity is given as :

t = 2π x number of revolutions / angular velocity

Therefore :

t = 2π x 6.9 / 3.1

t = 2 x 3.142 x 6.9 / 3.1

t = 43.3596/3.1

t = 13. 98696774194

to the nearest tenth

t = 13. 99s

7 0
3 years ago
En considérant que DE est
skad [1K]

Answer:

si

Step-by-step explanation:

5 0
3 years ago
Given the function: f(x) = 2x3 - 3/2x, find f(-4).
Sergeu [11.5K]

Answer:

D) -122

Step-by-step explanation:

Given:

f(x) = 2x^3-\frac{3}2x

We need to find f(-4).

Now by substituting the value of x =-4 in above equation we get;

f(-4)= 2\times(-4)^3-\frac{3}{2}\times(-4)\\

By using PEDMAS we will solve for exponential function first we get;

Now we know that (-4)^3=-64

So we get;

f(-4)= 2\times(-64)-\frac{3}{2}\times(-4)\\

Now using PEDMAS we will solve division.

f(-4)= 2\times(-64)-1.5\times(-4)

Now using PEDMAS we solve multiplication.

f(-4)= -128+6

Finally by subtraction we get;

f(-4)= -122

5 0
3 years ago
Given the information in the diagram below, find the measure of angle N. Use RACE and complete sentences to show how you found t
Sonja [21]

Answer:

m<N = 76°

Step-by-step explanation:

Given:

∆JKL and ∆MNL are isosceles ∆ (isosceles ∆ has 2 equal sides).

m<J = 64° (given)

Required:

m<N

SOLUTION:

m<K = m<J (base angles of an isosceles ∆ are equal)

m<K = 64° (Substitution)

m<K + m<J + m<JLK = 180° (sum of ∆)

64° + 64° + m<JLK = 180° (substitution)

128° + m<JLK = 180°

subtract 128 from each side

m<JLK = 180° - 128°

m<JLK = 52°

In isosceles ∆MNL, m<MLN and <M are base angles of the ∆. Therefore, they are of equal measure.

Thus:

m<MLN = m<JKL (vertical angles are congruent)

m<MLN = 52°

m<M = m<MLN (base angles of isosceles ∆MNL)

m<M = 52° (substitution)

m<N + m<M° + m<MLN = 180° (Sum of ∆)

m<N + 52° + 52° = 180° (Substitution)

m<N + 104° = 180°

subtract 104 from each side

m<N = 180° - 104°

m<N = 76°

4 0
3 years ago
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