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diamong [38]
3 years ago
12

Please help mee. Please help mee.

Mathematics
2 answers:
Luda [366]3 years ago
7 0
What do you need help with
Tresset [83]3 years ago
5 0
The thing won’t load bro
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graph 1 graph 2 graph 3 graph 4 Which graph represents the function f(x) = x2 + 3x + 2? A. graph 1 B. graph 2 C. graph 3 D. grap
stiv31 [10]

Answer:

See attachment

Step-by-step explanation:

To see clearly the graph that represents

f(x) =  {x}^{2}  + 3x + 2

we rewrite in vertex form to get;

f(x) = (x +  \frac{3}{2})^{2}  -  \frac{1}{4}

This is a vertical parabola with vertex at (-1.5,-0.25) and opens upwards.

The required graph is shown in the attachment.

3 0
3 years ago
Would someone do number 10 and 12
Sliva [168]

Answer:

they would divide it

Step-by-step explanation:

because that what some people would do

5 0
4 years ago
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
How many yards off the line of scrimmage does the pass rusher need to line up?
stich3 [128]

The pass rusher, which is typically line up on the line of scrimmage.

Have a Great Day :)

3 0
3 years ago
(X-2)²+(y-1)²=25 how do you do this problem?
Tasya [4]
(x-x_c)^2+(y-y_c)^2=r^2\\
(x_c,y_c) - \text{center}\\\\
(x-2)^2+(y-1)^2=25\\
\text{center}=(2,1)\\
r=\sqrt{25}=5
5 0
3 years ago
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