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just olya [345]
3 years ago
13

explain how you can tell whether a group of ratios represents a proportional relationship. PLEASE HELP

Mathematics
1 answer:
zubka84 [21]3 years ago
6 0
Ratios are proportional if they represent the same relationship. One way to see if two ratios are proportional is to write them as fractions and then reduce them. If the reduced fractions are the same, your ratios are proportional.

hope this helps :)
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Please help i need this done QUICK im timed ill give the best answer brainliest
seraphim [82]

Answer:

x=−32/5

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

1/2(1/4x−3/5)=1/4(2/5+3/4x)

(1/2)(1/4x)+(1/2)(−3/5)=(1/4)(2/5)+(1/4)(3/4x)(Distribute)(1/2)(1/4x)+(1/2)(−3/5)=(1/4)(2/5)+(1/4)(3/4x)(Distribute)

1/8x+−3/10=1/10+3/16x

1/8x+−3/10=3/16x+1/10

Step 2: Subtract 3/16x from both sides.

1/8x+−3/10−3/16x=3/16x+1/10−3/16x

−1/16x+−3/10=1/10

Step 3: Add 3/10 to both sides.

−1/16x+−3/10+3/10=1/10+3/10

−1/16x=2/5

Step 4: Multiply both sides by 16/(-1).

(16/−1)*(−1/16x)=(16/−1)*(2/5)

x=−3/25

7 0
3 years ago
I NEED HELP PLEASE, THANKS! :) Use the graph to determine the domain and range of the relation, and state whether the relation i
Mandarinka [93]

Answer:

Domain: All numbers greater than or equal to 0. By definition, the domain of a graph, is the possible x values.

Range: All real numbers. By definition, the range is all possible x values.

Not a function. A function has y value for every x value.

3 0
3 years ago
2
lutik1710 [3]

Answer:

\huge \boxed{\mathrm{804}}

Step-by-step explanation:

\sf The \ initial \  population \ of \ the \ town \ was \ 568.

\sf 236 \ migrated \ to \ the \ town.

568+236

=804

\sf The \ present \ population \ of \ the \ town \ is \ 804.

5 0
3 years ago
Read 2 more answers
Help pleaseeeeeerreeeeeeeeeeeeeeeee
N76 [4]
1
A coefficient is the number attached to a variable (k). In front of k is an implied 1 because k*1=k. So the coefficient of the third terms is 1
8 0
3 years ago
a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no
Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

\frac{sin A}{a} = \frac{sin B}{b}

Therefore,

\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}

α = Angle between radar and ship α

∴ α = 58.052

Where we put

\frac{sin 45}{6.25} = \frac{sin \alpha }{x} to get

\frac{x}{6.25} = \frac{sin \alpha }{sin 45} and differentiate to get

\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt}  }{sin 45}

\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt}  }= 3.208 degrees/second = 0.05599 rad/sec.

6 0
3 years ago
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