The temperature (in k) at which the density of this liquid will be equal to 1.183 g/cm³ is; 639.6 K
<h3>How to find the temperature from density?</h3>
We are given the formula for density as;
D = 1.246 g/cm³/(1 + 8.324 * 10⁻⁵ K⁻¹ × T)
Where D is density and T is absolute temperature (In K).
If we want a density of 1.183 g/cm³, then we have;
1.183 = = 1.246 g/cm³/(1 + 8.324 * 10⁻⁵ K⁻¹ × T)
Cross multiply to get;
1.183 + (1.183 * 8.324 * 10⁻⁵ * T) = 1.246
1.183 + 0.985 * 10⁻⁴T= 1.246
0.985 * 10⁻⁴T = 1.246 - 1.183
T = 0.063/( 0.985 * 10⁻⁴)
T = 639.6 K
Read more about Temperature and Density at; brainly.com/question/17231176
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Answer:
Smaller
Step-by-step explanation:
2 2/5 * 1/6 = 2/
5
= 0.4
Conversion a mixed number 2 2/
5
to a improper fraction: 2 2/5 = 2 2/
5
= 2 · 5 + 2/
5
= 10 + 2/
5
= 12/
5
To find a new numerator:
a) Multiply the whole number 2 by the denominator 5. Whole number 2 equally 2 * 5/
5
= 10/
5
b) Add the answer from previous step 10 to the numerator 2. New numerator is 10 + 2 = 12
c) Write a previous answer (new numerator 12) over the denominator 5.
Two and two fifths is twelve fifths
Multiple: 12/
5
* 1/
6
= 12 · 1/
5 · 6
= 12/
30
= 2 · 6/
5 · 6
= 2/
5
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(12, 30) = 6. In the following intermediate step, cancel by a common factor of 6 gives 2/
5
.
In other words - twelve fifths multiplied by one sixth = two fifths.
Answer:
the absolute value of |-13| is 13
Step-by-step explanation:
The single transformation that can be used to map T₁ onto T₂ is Rotate T₁ 180° about the origin.
<h3>What transformation would map T₁ onto T₂?</h3>
When a shape is rotated 180° about the origin, it means that the points go from (x, y) to (-x, -y).
The points on T₁ if rotated 180° about the origin would go from:
(-2, -2) to (2, 2)
(5, -6) to (-5, 6)
(5,0) to (-5, 0)
These are the points of T₂ so the way to map T₁ on T₂ is to use a 180° about the origin.
Find out more on rotating about the origin at brainly.com/question/16200542
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