Based on the definition of the diagonals of a rhombus, m∠AED = 90°.
<h3>What are the Diagonals of a Rhombus?</h3>
A rhombus has two diagonals that bisect each other at right angles, that is they are perpendicular to each other.
Angle 90 is formed at the intersection of the two diagonals of a rhombus.
In rhombus ABCD, ∠AED is formed at the intersection of the diagonals of the rhombus.
Therefore, based on the definition of the diagonals of a rhombus, m∠AED = 90°.
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Answer:
- 24.6 Nm north
- 67.7 Nm west
Step-by-step explanation:
In x-y coordinates, the direction is 70° CCW from 90° (north), so is 160° from the +x axis. In 4 hours at 18 Nm/h, the ship will travel 4×18 Nm = 72 Nm.
The coordinates in the x-y plane can be found to be ...
72(cos(160°), sin(160°)) ≈ (-67.7, 24.6)
The ship traveled 67.7 nautical miles west and 24.6 nautical miles north from the port.
Answer:
The resulting three-dimensional object will be a cone
Step-by-step explanation:
Plot the figure to better understand the problem'
we have
a triangular cross-section with coordinates at (1, 1), (1, 4), and (3, 1)
The draw in the attached figure
we know that
When rotating a a right triangle about a leg, the three dimensional figure formed is a cone
The radius of the cone will be equal to the base of right triangle and the height of the cone will be equal to the height of the triangle
so
The radius of the cone will be equal to 2 units and the height of the cone will be 3 units
see the attached figure to better understand the problem
Answer:
Nope.
Step-by-step explanation:
area square: s^2 if one side is 2 cm: are ais 4 cm
rhombus square: (big diagonalxsmall diagonal)/2
what counts on the rombus is not the side, but the diagonals. The diagonals are usually longer than the side of the square, so the area of the rombus is bigger.