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Helen [10]
3 years ago
6

HELLPP I WILL GIVE BRAINLY

Physics
2 answers:
Alborosie3 years ago
8 0

Answer:

The energy conversion is:

C) Chemical - - - - > Thermal.

slava [35]3 years ago
3 0
Chemical to thermal
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How much work is done against gravity when lifting a 2-kg sack of groceries a distance of 2.5 meters?
Crazy boy [7]
W = F x d/x = (m x Ag) x h, therefore, mass (2kg x 9.8) x 2.5m = 49J
8 0
3 years ago
A crystalline grain of nickel in a metal plate is situated so that a tensile load is oriented along the [111] crystal direction
hoa [83]

Given:

Applied stress, \sigma = 0.45 MPa

Critical Resolved Stress,  T_{cRss}= 0.242 MPa

Solution:

a). According to the question, orientation of tensile load is along [1 1 1],

\sigma = 0.45 MPa

Now, for resolved shear stress,  \t_{Rss} along [1 0 1] within (1 1 T)

let  '\theta' be the angle between [1 1 1] and [1 0 1], then by coordinate formula:

cos\theta = \frac{1\times 1 + 1\times 0 + 1\times 1}{\sqrt{1^{2}+1^{2}+1^{2}\sqrt{1^{2}+0^{2}+1^{2}}}}

cos\theta = \sqrt{\frac{2}{3}}

let  '\phi' be the angle between [1 1 1] and [1  1 1], then by coordinate formula:

cos\phi  = \frac{1\times 1 + 1\times 1 + 1\times 1}{\sqrt{1^{2}+1^{2}+1^{2}\sqrt{1^{2}+1^{2}+1^{2}}}}

cos\phi = 1

Now, for the resolved components along [1 0 1]

\t_{Rss}  = \sigma  cos\theta cos\phi

\t_{Rss} = 0.45\times 10^{6}\times \sqrt{\frac{2}{3}}\times 1 = 0.3673 MPa

b).  For required tensile stress to produce  T_{cRss}= 0.242 MPa:

\sigma _{1} = \frac{T_{cRss}}{cos\theta  cos\phi }

\sigma _{1} = \frac{0.242\times 10^{6}}{\sqrt{\frac{2}{3}}\times 1}

\sigma _{1} = 0.2964 MPa

5 0
3 years ago
What is the name of the particle that compounds are made of?
VashaNatasha [74]

Answer:

Explanation:

atoms

8 0
3 years ago
What is the wavelength of a wave that is traveling at 343 m/s with a frequency of 1000 Hz
ZanzabumX [31]

Answer:

343 \div 1000 = 0.343

wavelength is equivalent to the velocity divided by the frequency

3 0
3 years ago
At some airports there are speed ramps to help passengers get from one place to another. A speed ramp is a moving conveyor belt
Amanda [17]

Answer:

The time taken is t_s = 31.16 s

Explanation:

From the question we are told that

   The length of the speed ramp is L = 104m

     The speed of the speed ramp is v_r  = 2.1 m/s

      The time taken to cover the distance is t = 84 s

     

The walking speed( when not on the speed ramp)  required to  cover the 104m is mathematically represented as

                     v_w = \frac{L}{t}

Substituting values

                      v_w = \frac{104}{84}

                            = 1.238 m/s

The speed required to cover the 104m distance when on a speed speed ramp  is mathematically represented as

     v = The\ walking\ speed  +  speed \ of \ the \ speed \ ramp

 substituting values

               v = 2.1 + 1.238

               v = 3.338 m/s

Now the time taken to travel the 104m distance when walking on the speed ramp is mathematically evaluated as

                t_s = \frac{L}{v}

                     = \frac{104}{3.338}

                     t_s = 31.16 s

             

4 0
3 years ago
Read 2 more answers
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