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timama [110]
3 years ago
6

Write a quadratic equation could some please help asap​

Mathematics
1 answer:
True [87]3 years ago
6 0

Answer:

f(x) = x^2 + 3x + 2.

Step-by-step explanation:

The zeroes of the quadratic function are -1 and -2 so we can write it as:

f(x) = a(x + 1)(x + 2)    where  a is some constant.

Now, when x = 1,  f(x) = 6 so

6 = a(1+1)(1+2)

6 = a*2*3 = 6a

a = 1.

So the function is f(x) = (x + 1)(x + 2) = x^2 + 3x + 2.

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Arte-miy333 [17]

Answer:

56

Step-by-step explanation:

3 0
3 years ago
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WILL GIVE POINTS AND BRAINLIEST
agasfer [191]

Answer: The patterns on that chart is the years of the different cases

Step-by-step explanation: One is talking about the cases in year 1931-40 and the other is 1941-50.

Also, let me tell you a history of those cases. In 1912, measles became a nationally notifiable disease in the United States, requiring U.S. healthcare providers and laboratories to report all diagnosed cases. In the first decade of reporting, an average of 6,000 measles-related deaths were reported each year.

In the decade before 1963 when a vaccine became available, nearly all children got measles by the time they were 15 years of age. It is estimated 3 to 4 million people in the United States were infected each year. Also each year, among reported cases, an estimated 400 to 500 people died, 48,000 were hospitalized, and 1,000 suffered encephalitis (swelling of the brain) from measles.

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8 0
2 years ago
Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we
Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N(\mu = 7 lbs , \sigma^{2}  = 0.875^{2}  lbs)

The standard normal z distribution is given by;

              Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean weight

             n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{7.5-7}{\frac{0.875}{\sqrt{4} } }  ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0
3 years ago
1........... 5x (3x +2)
babymother [125]

You do 3832083082x 32u393829832983x to get this 5,418

7 0
2 years ago
In a right angle triangle the side lengths are 4 and 2. Please find the hypotenuse. You can answer this in radical form OR give
Ghella [55]

Answer:

4.47

Step-by-step explanation:

A squared + B squared = C squared

4*4=16 2*2=4  16+4=20  

the square root of 20 is 4.472135955, rounded to the nearest hundreth is 4.47

7 0
3 years ago
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