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timama [110]
3 years ago
6

Write a quadratic equation could some please help asap​

Mathematics
1 answer:
True [87]3 years ago
6 0

Answer:

f(x) = x^2 + 3x + 2.

Step-by-step explanation:

The zeroes of the quadratic function are -1 and -2 so we can write it as:

f(x) = a(x + 1)(x + 2)    where  a is some constant.

Now, when x = 1,  f(x) = 6 so

6 = a(1+1)(1+2)

6 = a*2*3 = 6a

a = 1.

So the function is f(x) = (x + 1)(x + 2) = x^2 + 3x + 2.

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The x intercepts of the function f(x) = 2x(x-5)^2(x+4)^3<br> are…
Leokris [45]

Answer:

\boxed{\sf x- intercepts = 0 , 5 \ and \ -4}

Step-by-step explanation:

A function is given to us and we need to find the x Intercepts of the graph of the given function . The function is ,

\sf \implies f(x) = 2x( x - 5 ) ^2(x+4)^3

For finding the x intercept , <u>equate the given function with 0, we have ;</u>

\sf \implies 2x ( x - 5 )^2(x+4)^3= 0

Equate each factor with 0 ,

\sf \implies 2x = 0

Divide both sides by 2 ,

\sf \implies\bf x = 0

Again ,

\sf \implies ( x - 5)^2=0

Taking squareroot on both sides,

\sf \implies x - 5 = 0

Add 5 to both sides,

\sf \implies \bf x = 5

Similarly ,

\sf \implies \bf x = -4

<u>Hence</u><u> the</u><u> </u><u>x </u><u>Intercepts</u><u> </u><u>are </u><u>-</u><u>4</u><u> </u><u>,</u><u> </u><u>0</u><u> </u><u>and </u><u>5</u><u> </u><u>.</u>

{ See attachment also for graph } .

3 0
3 years ago
A panda and a giraffe start moving towards each other when they are 300 feet apart. The panda is running at a speed of P feet pe
liq [111]

Answer:

(2P + G) feet/min

Step-by-step explanation:

Speed of the panda = P

Speed of the giraffe = P + G

Thus,

Speed of Panda + Speed of Giraffe = approaching time

= P + P + G

= <u>2P + G</u>

Thus, The panda and the giraffe are approaching each other at a rate

of <u>(2P + G) ft/min</u>

<u></u>

<em>Hope it helps :)</em>

6 0
3 years ago
I need help with this <br><br> 10 points <br><br> Pls pls pls someone come help me
Vikki [24]

Answer:

angle b is 62 degrees. This is because if we solve for x, by putting the 2 equations equal to each other(because they are vertical angles), than we figure out that x=6. Now plug that into angle b's equation, and you get 62 degrees.

Step-by-step explanation:

7 0
4 years ago
Solve the following system of equations and show all work.<br> y = 2x^2 +9x<br> y = 4x + 25
Genrish500 [490]

Answer:

x = 5/2 thì y = 35 và x = -5 thì y = 5

Step-by-step explanation:

thay y = 4x + 25 vào phương trình y = 2x ^ 2 + 9x ta có:

4x + 25 = 2x ^ 2 + 9x

⇒2x ^ 2 + 5x - 25 = 0

⇒ x = 5/2 và x = -5

thay x = 5/2 vào phương trình y = 4x + 25 ⇒ y = 4*(5/2) + 25 = 35

thay x = -5 vào phương trình y = 4x + 25 ⇒ y = 4*(-5) + 25 = 5

7 0
3 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
3 years ago
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