Answer:
1) 250°, 2) 44°
Step-by-step explanation:
1) See attached
If we add a line ⊥ to both AB and DE, we can find x as a sum of 2 internal angles of right triangles and 180°
∠D internal = 360°-312°=48°
x=180°+(90°-62°)+(90°-48°)= 180°+28°+42°= 250°
x=250°
2)
∠ADC= ∠ABC= 180°- ∠ADE= 180°- 110°= 70°
∠DBC= ∠ABC- ∠ABD= 70°-26°= 44°
∠DBC= 44°
5x + 20
5(x) + 5(4)
5(x + 4)
The problem is in the picture that you showed
Answer: hello your question is poorly written hence I will provide the required matrix
answer :
A = ![\left[\begin{array}{ccc}1&0&1\\0&1&1\\1&-1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%261%5C%5C0%261%261%5C%5C1%26-1%260%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given that the basis of the orthogonal complement have been provided already by you in the question I will have to provide the Matrix
The required matrix
![\left[\begin{array}{ccc}1&0&1\\0&1&1\\1&-1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%261%5C%5C0%261%261%5C%5C1%26-1%260%5Cend%7Barray%7D%5Cright%5D)
column1 = column 3 - column2
where column 3 and column 2 are the basis of the orthogonal complement of the column space of the Matrix