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Archy [21]
3 years ago
6

How do you solve for x: 2x/3 = 3x/5 - 1 ???

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

x=-15

Step-by-step explanation:

2x/3=3x/5-1

10x=9x-15

10x-9x=-15

x=-15

you need to use the least common multiple which are 3,5

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2) A construction contractor used the equation 11.52=(1.44)8 to
Rina8888 [55]

Answer:

2.88

Explanation:

If you break down the equation we see that 8 is the number of boxes and 1.44 is the price of each box. So if you wanted to change the equation the formula would be: (1.44)x = cost so if you wanted to figure out how much 2 boxes would be, you just plug in 2 for x and you get (1.44)2 = 2.88

5 0
3 years ago
Which statement about dilation and rotation is true?
arlik [135]

Answer:

answer choice c

Step-by-step explanation:

C. Both dilation and rotation preserve angle.

7 0
3 years ago
Please help with my last question.
Bas_tet [7]

Answer:

x = 8.3

y = 20.3

Step-by-step explanation:

21-\frac{2}{3} = 20\frac{1}{3} or 20.3

9-\frac{2}{3} = 8\frac{1}{3} or 8.3

6 0
2 years ago
After each soccer practice Scott Runs 4 sprints of 10 yards each complete exclamation to find how many practices it will take fo
Tpy6a [65]

Answer:

Scott will have to do 44 practices

Step-by-step explanation:

Let X be the number of yards per practice.

Let P = number of practice Scott needs to do.

Multiply 20 yards by 4 sprints

X = 20yards × 4 sprints = 80 yards

Number of yards he had to sprint per practice will be:

1 mile = 1760 yards

Converting from miles to yards

X = 1760 × 2 miles = 3520 yards

Number of practice,P Scott need to do = (3520/80)yards

Number of Practice,P = 44

5 0
3 years ago
Read 2 more answers
Expand the equation (p+q)^5
VashaNatasha [74]
(p + q)⁵
(p + q)(p + q)(p + q)(p + q)(p + q)
{[p(p + q) + q(p + q)][p(p + q) + q(p + q)](p + q)}
{[p(p) + p(q) + q(p) + q(q)][p(p) + p(q) + q(p) + q(q)](p + q)}
(p² + pq + pq + q²)(p² + pq + pq + q²)(p + q)
(p² + 2pq + q²)(p² + 2pq + q²)(p + q)
{[p²(p² + 2pq + q²) + 2pq(p² + 2pq + q²) + q²(p² + 2pq + q²)](p + q)}
{[p²(p²) + p²(2pq) + p²(q²) + 2pq(p²) + 2pq(2pq) + 2pq(q²) + q²(p²) + q²(2pq) + q²(q²)](p + q)}
(p⁴ + 2p³q + p²q² + 2p³q + 4p²q² + 2pq³ + p²q² + 2pq³ + q⁴)(p + q)
(p⁴ + 2p³q + 2p³q + p²q² + 4p²q² + p²q² + 2pq³ + 2pq³ + q⁴)(p + q)
(p⁴ + 4p³q + 6p²q² + 4pq³ + q⁴)(p + q)
p⁴(p + q) + 4p³q(p + q) + 6p²q²(p + q) + 4pq³(p + q) + q⁴(p + q)
p⁴(p)+ p⁴(q) + 4p³q(p) + 4p³q(q) + 6p²q²(p) + 6p²q²(q) + 4pq³(p) + 4pq³(q) + q⁴(p) + q⁴(q)
p⁵ + p⁴q + 4p⁴q + 4p³q² + 6p³q² + 6p²q³ + 4p²q³ + 4pq⁴ + pq⁴ + q⁵
p⁵ + 5p⁴q + 10p³q² + 10p²q³ + 5pq⁴ + q⁵
7 0
3 years ago
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