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UkoKoshka [18]
3 years ago
12

What happens to the speed of motion of the particles of a gas when a certain volume of the gas is heated at constant pressure? E

xplain your answer.
Chemistry
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

As the gas is heated, the particles will begin to move faster. ... Because the gas remains at a constant pressure and volume, the particles cannot spread out so they simply move around the container even faster.

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How does the energy of an electorn change when the electron moves closer to the nucleus?
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1 year ago
The constant volume heat capacity of a gas can be measured by observing the decrease in temperature when it expands adiabaticall
miv72 [106K]

Answer:

The value is  C_p  = 42. 8 J/K\cdot mol

Explanation:

From the question we are told that  

     \gamma = \frac{C_p }{C_v}

The  initial volume of the  fluorocarbon gas is  V_1 = V

 The final  volume of the fluorocarbon gas isV_2 = 2V

  The initial  temperature of the fluorocarbon gas is  T_1  =  298.15 K

  The final  temperature of the fluorocarbon gas is T_2  =  248.44 K

   The initial  pressure is P_1  = 202.94\  kPa

    The final   pressure is  P_2  =  81.840\  kPa

Generally the equation for  adiabatically reversible expansion is mathematically represented as

       T_2 =  T_1  * [ \frac{V_1}{V_2} ]^{\frac{R}{C_v} }

Here R is the ideal gas constant with the value  

        R =  8.314\  J/K \cdot mol

So  

   248.44 =   298.15  * [ \frac{V}{2V} ]^{\frac{8.314}{C_v} }

=> C_v  =  31.54 J/K\cdot mol

Generally adiabatic reversible expansion can also be mathematically expressed as

    P_2 V_2^{\gamma} = P_1 V_1^{\gamma}

=>[ 81.840 *10^3] [2V]^{\gamma} = [202.94 *10^3] V^{\gamma}    

=>  2^{\gamma} =  2.56

=>    \gamma =  1.356

So

     \gamma  =  \frac{C_p}{C_v} \equiv  1.356 = \frac{C_p}{31.54}

=>    C_p  = 42. 8 J/K\cdot mol

3 0
3 years ago
Convert 150 g/L to the unit g/mL.<br><br> 15,000 g/mL<br> 15 g/mL<br> 0.15 g/mL<br> 0.0015 g/mL
fredd [130]
1 g/L ------- 0.001 g/mL
150 g/L ----- ?

150 x 0.001 / 1

= 0.15 g/mL

Answer C
6 0
3 years ago
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Which of the following will form a metallic bond with a metal?
lisabon 2012 [21]
It’s really any metal because metals form metallic bonds. They are the only substances which can make metallic bonds. So the answer is A
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