Answer:
that is why co2 is in the power of 2ik
So I’m not 100% sure what you’re asking but I’m going to give it a go. The elimination reaction is a term used in organic chemistry that describes a type of reactions. The name kinda tells you what’s going to happen. Something is going to be removed/eliminated from initial reactant/substrate and as a result, an alkene (double bond containing compound) will form.
In elimination reactions a hydrogen atom is first removed (as a H+) from the beta carbon. As a result, the left behind electrons create a pi bond between the beta carbon and the neighboring alpha carbon. This promotes the electronegative atom, on the alpha carbon, to leaves the substrate taking both electrons from the shared sigma bond with the alpha carbon.
Answer:
<h2>9.03 × 10²³ atoms </h2>
Explanation:
The number of atoms of Al can be found by using the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 1.5 × 6.02 × 10²³
We have the final answer as
<h3>9.03 × 10²³ atoms</h3>
Hope this helps you
Answer: Catalyst
Explanation: it speeds it up lol but basically the catalyst helps speed up the chemical reaction by reducing the activation energy or changing the reaction machenism/
Answer: The value of
for the half-cell reaction is 0.222 V.
Explanation:
Equation for solubility equilibrium is as follows.

Its solubility product will be as follows.
![K_{sp} = [Ag^{+}][Cl^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D)
Cell reaction for this equation is as follows.

Reduction half-reaction:
, 
Oxidation half-reaction:
,
= ?
Cell reaction: 
So, for this cell reaction the number of moles of electrons transferred are n = 1.
Solubility product, ![K_{sp} = [Ag^{+}][Cl^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D)
= 
Therefore, according to the Nernst equation
At equilibrium,
= 0.00 V
Putting the given values into the above formula as follows.

= 
= 0.577 V
Hence, we will calculate the standard cell potential as follows.



= 0.222 V
Thus, we can conclude that value of
for the half-cell reaction is 0.222 V.