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Vitek1552 [10]
3 years ago
6

What is the molar mass of C3H8? a) 44.0 g b)11.0 g c)36.0 g d)6.02 × 1023 g

Chemistry
2 answers:
Ainat [17]3 years ago
7 0

Answer: (A) 44.0 g/mol

Explanation:

Molar mass of a compound is the sum total of all the individual masses of the constituent elements present in the compound.

Molar mass of C3H8 =

C = 12.0 g/mol

H = 1.00 g/mol

Molar mass of C3H8 = (12*3) + (1*8) = 36 + 8 = 44 g/mol.

Molar mass of C3H8 = 44g/mol

Andrew [12]3 years ago
4 0

C = 12 g/mol  

H= 1 g/mol  

<em> C3H8  </em>

<u>C: 12 g/mol * 3 = 36 g/mol  </u>

<u>H: 1 g/mol * 8 = 8 g/mol  </u>

<em> 36 + 8 = 44 g/mol</em>

Answer: A) 44.0 g

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Calculate the molarity of a solution obtained dissolving 10.0 g of cobalt(Ⅱ) bromide tetrahydrate in enough water to make 450 mL
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<em><u>The molarity of the CoBr2•4H2O solution is  7.64 × 10-2 M</u></em>

Explanation:

Cobalt (II) bromide tetrahydrate

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• Bromide - anion from group 7A → -1 charge → symbol: Br-

• Tetrahydrate- tetra- means 4 and hydrate is H2O

The chemical formula of the compound is: CoBr2•4H2O

We then need to determine the number of moles of CoBr2•4H2O since this is the only information missing for us to find molarity. Notice that the volume of the solution is already given.

We’re given the mass of CoBr2•4H2O. We can use the molar mass of CoBr2•4H2O4 to find the moles.

•The molar mass of CoBr2•4H2O is:

CoBr2•4H2O  

1 Co x 58.93 g/mol Co = 58.93 g/mol

2 Br x 79.90 g/mol Br = 159.80 g/mol

8 H  x 1.008 g/mol H = 8.064 g/mol

4 O  x 16.00 g/mol O = 64.00 g/mol

________________________________________

                           Sum = <u>290.79 g/ mo</u>

The moles of CoBr2•4H2O is:

= 10.0 g CoBr2•4H2O x  \frac{ 1 mol  CoBr_2 . 4H_2O}{290.79 g CoBr_2 .  4H_2O}

= <u>0.0344  mol CoBr2•4H</u>

We know that the volume of the solution is 450 mL.

We can now calculate for molarity:

Convert mL to L → 1 mL = 10-3 L

Formula:

Molarity (M)= Mole of solute / Liters of solution

= 0.0344  mol CoBr2•4H  / 450 mL x 1 ml / 10^ -3 L

= 0.0764

=  7.64 × 10-2 mol/L

8 0
3 years ago
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