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3 years ago

Describe how to test your unknown salt mixture for the presence ofNa3PO4.12H2O.

Chemistry

1 answer:

klemol [59]3 years ago

6 0

Na3PO4*12H2O + BaCl2*2H2O = Ba3(PO4)2 + NaCl + H2O

add barium chloride to your Na3PO4.12H2O a white precipitate of Ba3(PO4)2 will be formed wrt salt(NaCl) and water(H20) if Na3PO4.12H2O. will be there.

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3 years ago

What is the mass in grams of 2.6 moles of angelic acid?

Dennis_Churaev [7]

Answer:

260.34g

Explanation:

First, you need to know what angelic acid is comprised of. It is written as C₅H₈O₂.

In order to solve for the mass of 2.6 moles of angelic acid, you need the mass of 1 mole of angelic acid. This can be found by adding the masses from the periodic table, like shown below:

5 carbon atoms = (5)(12.01g) = 60.05g

8 hydrogen atoms = (8)(1.01) = 8.08g

2 oxygen atoms = (2)(16) = 32g

angelic acid = 60.05 + 8.08 + 32 = 100.13g

Then, set up a basic stoichiometric equation and solve. The units should cancel out.

$(\frac{2.6mol}{1} )(\frac{100.13g}{1mol} )=260.34g$

5 0

3 years ago

Balance the following equations:

lesya [120]

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(II) $P_{4} + 5O_{2} --> 2P_{2} O_{5}$

(III) $2NaF + Br_{2} -->2NaBr + F_{2}$

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7 0

3 years ago

Two samples of a compound containing elements a and b are decomposed. the first sample produces 15 g of a and 35 g of

Alborosie

According to law of definite proportion, for a compound, elements always combine in fixed ratio by mass.

The formula of compound remains the same, let it be a_{x}b_{y} where, a and b are two different elements.

Since, the ratio of mass remains the same , calculate the ratio of masses of element a and b in both cases

\frac{a}{b}=\frac{15}{35}=\frac{10}{y}

rearranging,

y=\frac{10\times 35}{15}=23.3

Thus, mass of b produced will be 23.3 g.

3 0

3 years ago

Which elements are in the same period?

worty [1.4K]

Answer:

Elements that are in the same period have chemical properties that are not all that similar. Consider the first two members of period 3: sodium (Na) and magnesium (Mg). In reactions, they both tend to lose electrons (after all, they are metals), but sodium loses one electron, while magnesium loses two.

Explanation:

(Hoped this helped! :D)

5 0

3 years ago

Describe how to test your unknown salt mixture for the presence ofNa3PO4.12H2O.​

Describe how to test your unknown salt mixture for the presence ofNa3PO4.12H2O.