2 years ago

The volume of 1.20 lol of gas at 61.3 kPa and 25.0 degree Celsius is

Chemistry

1 answer:

aniked [119]2 years ago

4 0

Answer:

V = 48.5 L

Explanation:

Converting °C to K and kPa to atm

T = 25.0°C + 273.15 = 298.15 K

P = 61.3 kPa × (1 atm / 101.325 kPa) = 0.60498 atm

Calculating the volume of gas

V = nRT / P

V = (1.20 mol)(0.082057 L•atm/mol•K)(298.15 K) / 0.60498 atm

V = 48.5 L

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