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ioda
3 years ago
6

Why does a solution of a weak base and its conjugate acid act as a better buffer than does a solution?

Chemistry
1 answer:
german3 years ago
7 0
Hello!

A solution of a weak base and its conjugate acid act as a better buffer than does a solution of a weak base alone because <span>A solution of a weak base alone has no acid present to absorb added base.</span> 

If an acid (In this case HCl) is added to a buffer or a weak base solution, the following reaction happens:

HCl + A⁻ → HA + Cl⁻

In this way, the addition of acid is neutralized by the base.

If a base is added (In this case NaOH), only a solution of a weak base and its conjugate acid can react in the following way:

NaOH + HA → NaA + H₂O

So, a solution of only a weak base can resist the addition of acids but not bases, so it isn't a good buffer. 

Have a nice day!
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love history [14]

Answer:

1. Stąd empiryczny wzór substancji to N₂O₅

2. W związku z tym ilość w gramach chlorku sodu NaCl is 114,4 g.

Explanation:

1. Mamy tutaj;

Masa molowa tlenku azotu = 108u

Masa azotu = 14,0067u

Masa tlenu = 15,999 u

74,07% masy tlenku azotu to tlen

Dlatego masa obecnego tlenu = 108 × 74,07 / 100 = 79,9956 u

Masa obecnego azotu = 108 - 79,9956 = 28,0044u

Liczba moli tlenu = 79,9956 / 15,999 = 5,00003 ≈ 5

Liczba moli azotu = 28,0044 / 14,0067 = 1,99935 ≈ 2

Stąd empiryczny wzór substancji to N₂O₅.

2. Kiedy sód reaguje z chlorem, mamy;

2Na (s) + Cl₂ (g) → 2NaCl (s)

Dlatego 2 mole sodu Na reaguje z 1 molem chloru gazowego Cl₂, z wytworzeniem 2 moli chlorku sodu NaCl

W związku z tym 1 mol sodu Na reaguje z 1/2 molem chloru gazowego Cl₂ z wytworzeniem 1 mola chlorku sodu NaCl

Masa Na obecnego w reakcji = 45 g

Masa molowa sodu = 22,989769u

Liczbę moli sodu w 45 g sodu podano w następujący sposób;

Liczba \, \, moli \, \, Na= \frac{Mass \, of \, Na}{Molowy \, masa \, z \, Na} = \frac{45}{22.989769} = 1.96 \, mole

Z czego 1,96 moli sodu Na reaguje z 1/2 × 1,96 mola chloru gazowego Cl₂ z wytworzeniem 1,96 mola chlorku sodu NaCl

Masa molowa NaCl = 58,44 g / mol

Dlatego masa NaCl = liczba moli NaCl × masa molowa NaCl

Masa NaCl = 1,96 × 58,44 = 114,39001 g ≈ 114,4 g

W związku z tym ilość w gramach chlorku sodu NaCl = 114,4 g.

4 0
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You may know these information:

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PbBr₂ is formed, so this will be our precipitate

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4 0
2 years ago
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