Answer:
The orbital shapes are actually representation of (Ψ)2 all over the orbit simplified ... ψnlml(r,θ,ϕ)=Rnl(r)Ymll(θ,ϕ) , ... and thus it is directly linked to the angular and radial nodes. ... for different quantum values(which can be assigned to different orbitals are ) .... The two types of nodes are angular and radial.
Explanation:
hope it helps
Answer:
A. They can not be divided.
Thank you.
BY GERALD GREAT.
Answer:
in crystalline solids
<em>Hope</em><em> </em><em>this</em><em> </em><em>answers</em><em> </em><em>your</em><em> </em><em>question</em><em>,</em><em> </em><em>good</em><em> </em><em>luck</em><em> </em>
Answer:
The calculations are in the explanation below.
The <em>steps </em>are:
- 1. Using a graduated pipette, accurately take 25mL of the 12.0M stock solution.
- 2. Pour the 25mL of stock solution into a 100 mL volumetric flask
- 3. Add distilled water up to the mark
- 4. Cap the flask with the stopper
- 5. Stirr by gently rotating the flask.
Explanation:
To make 100 mililiter of the 3.0M solution of sulfuric acid, first you must calculate the volume of the 12.0M stock solution that contains the same number of moles as the diluted solution.
For that, you use the dilution formula:
- number of moles = C₁V₁ = C₂V2
- V₁ = 3.0M × 100mL/12.0M = 25mL
Then, the steps are:
1. Using a graduated pipette, accurately take 25mL of the 12.0M stock solution.
2. Pour the 25mL of stock solution into a 100 mL volumetric flask
3. Add distilled water up to the mark
4. Cap the flask with the stopper
5. Stirr by gently rotating the flask.
