Answer:
O2
Explanation:
for find the limiting reactant you must calculate the moles of the reactants from the amount that you have and from the MM:
MM FeS2 = 120n = 26.2g / 120g/mol = 0,218 mol
MM O2 = 32n = 5,44g/32g/mol = 0,17 mol
The limiting reactant is
O2
Answer:
mole fraction hexane 0.64
Explanation:
We know from Raoult's law of partial pressures that for a binary mixture, the vapor pressure above solution is the sum of the partial pressures of each gas:
P total = P(A) + P(B)
Also the partial pressure of a component is the product of its mole fraction , X, times its pure vapor pressure:
Ptotal = X (A)Pº(A) + X (B)Pº(B)
Since for solution of two components the mole fractions add to one, we now have all the information required to compute the answer.
250 torr = X(hexane)151 torr + ( 1 - X(hexane) )425 torr
250 = 151X(hexane) + 425 - 425 X(hexane)
274 X(hexane) = 175
X(hexane) = 1 -0.6 = 0.64
