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3 years ago

Is there a mathematical pattern in the number of

Chemistry

1 answer:

aleksandrvk [35]3 years ago

4 0

Answer:

The orbital shapes are actually representation of (Ψ)2 all over the orbit simplified ... ψnlml(r,θ,ϕ)=Rnl(r)Ymll(θ,ϕ) , ... and thus it is directly linked to the angular and radial nodes. ... for different quantum values(which can be assigned to different orbitals are ) .... The two types of nodes are angular and radial.

Explanation:

hope it helps

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Ohanna is studying what happens to the energy as a ball rolls down a ramp. What is she studying? Check all that apply.

Softa [21]

Gravitational potential energy, mechanical energy, and kinetic energy.

7 0

3 years ago

A sample of an unknown compound is vaporized at . The gas produced has a volume of at a pressure of , and it weighs . Assuming t

Likurg_2 [28]

Answer:

The answer is " $34 \ \frac{g}{mol}$ "

Explanation:

Please find the complete question in the attached file.

Formula:

$\to PV = nRT\\\\n = \frac{mass}{MW} \\\\PV = \frac{mRT}{MW}\\\\MW = \frac{mRT}{(PV)}\\\\MW = \frac{(0.941)(0.082)(150+273)}{(1 \times 0.96)}$

$= \frac{(0.941)(0.082)(423)}{(0.96)} \\\\= \frac{32.639526}{(0.96)} \\\\= 33.9995062\ \ \ or \ \ \ 34 \ \frac{g}{mol}$

8 0

3 years ago

Rank the following solutions from lowest to highest vapor pressure.

Fantom [35]

Solution :

When non volatile solute is added to solvent, vapor pressure gets lowered.

Relative lowering in vapor pressure is given :

$\frac{P^0-P}{P^0}$ = $\text{mole fraction}$ of solute

$\frac{P^0-P}{P^0}=x_B$

$P^0$ = vapor pressure of pure solvent

P = vapor pressure of solution

$x_B$ = mole fraction of solute

$x_B=\frac{n_B}{n_A+n_B}$

$n_B$ = $\text{number of moles of solute}$

$n_A$ = $\text{number of moles of solvent}$

Number of moles $=\frac{\text{weight}}{\text{molecular weight}}$

$\frac{P^0-P}{P^0}=\frac{w_B/M_B}{w_A/M_A+w_B/M_B}$

$\approx \frac{w_B/M_B}{w_A/M_A}$

1. For 10 g of $CH_3COOK$

$CH_3COOK \rightarrow CH_3COO^- + K^+$

Ions = 2

It will affect colligative property.

$\frac{P^0-P}{P^0} = \frac{i \times 10/98}{w_A/M_A}$

Relative lowering in vapor pressure will be :

$=\frac{2 \times 10/98}{w_A/M_A}$

$=\frac{0.20}{w_A/M_A}$

2. For 20 g sucrose

Sucrose is non electrolyte, i = 1

$\frac{P^0-P}{P^0} = \frac{ 20/342}{w_A/M_A}$

$=\frac{0.050}{w_A/M_A}$

3. For 20 g of glucose.

Glucose is a non electrolyte, i = 1

$\frac{P^0-P}{P^0} = \frac{20/180}{w_A/M_A}$

$=\frac{0.11}{w_A/M_A}$

$w_A/M_A$ is same in all three solutions.

Hence, lowering in vapor pressure is maximum in $CH_3COOK$ and minimum is Sucrose.

Vapor pressure from lowest to highest.

10 g of $CH_3COOK$ < 20 g of glucose < 20 g of sucrose

6 0

3 years ago

A chemical reaction gives off 2100 kg of heat energy how many calories

dlinn [17]

The chemical reaction that gives off 2100 Kg of heat energy has 501.9126 calories

calculation

convert KJ to calories

that is

1 KJ = 0.239006 calories

2100KJ= ? calories

by close multiplication

= (2100 kj x 0.239006)÷ 1 kj =501.9126 calories

7 0

3 years ago

how many grams of silver chloride (AgCI) can be produced if you start with 4.62 grams of barium chloride (BaCI2)

UkoKoshka [18]

The chemical equation representing the reaction of silver nitrate with barium chloride:

$2AgNO_{3}(aq) + BaCl_{2}(aq)--> 2AgCl (s) + Ba(NO_{3})_{2}(aq)$

Given mass of barium chloride = 4.62 g

Moles of $BaCl_{2} = 4.62 g BaCl_{2}*\frac{1 mol BaCl_{2}}{208.23 g BaCl_{2}} = 0.0222 mol BaCl_{2}$

Moles of AgCl = $0.0222 mol BaCl_{2} * \frac{2 mol AgCl}{1 mol BaCl_{2}}$ = 0.0444 mol AgCl

Mass of AgCl = $0.0444 mol AgCl * \frac{143.32 g AgCl}{1 mol AgCl} = 6.36 g AgCl$

6 0

3 years ago

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